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nevsk [136]
2 years ago
5

What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?

Mathematics
2 answers:
Iteru [2.4K]2 years ago
5 0
It is A because I did 100 times 200 and I got 200,000
Basile [38]2 years ago
5 0
Your answer is 0.5 s. I just took the test:))


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On January 1, year 1, Klondike issued 10-year bonds with a stated rate of 10% and a face amount of $100,000. The bonds pay inter
Nataliya [291]

Answer:

91,000

Step-by-step explanation:

4 0
2 years ago
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Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.
alexdok [17]

Answer:

The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.

There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9

Therefore for each and every one of the nine first digits there are 5 digits that the second can be.

Therefore ANSWER = 9 * 5 = 45 possible permutations.

2. The largest two digit number = 99

Subtract 57 and you get 42

ANSWER = 42

The forty two numbers are 58 ,59, 60, 61......98, 99

7 0
2 years ago
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Geoffrey is evaluating the expression StartFraction (negative 3) cubed (2 Superscript 6 Baseline) Over (Negative 3) Superscript
makkiz [27]

The mathematical expression does not seem clear but I have made an attempt to make sense of what is implied.

Answer:

<em>a</em> = 4, <em>b</em> = 2, <em>c</em> = 16, <em>d</em> = 9

Step-by-step explanation:

\dfrac{(-3)^3(2^6)}{(-3)^5(2^2)} = \dfrac{(2)^a}{(-3)^b} = \dfrac{c}{d}

Solving the first part of the question by indices,

\dfrac{(-3)^3(2^6)}{(-3)^5(2^2)} = (-3)^{3-5}(2)^{6-2} = (-3)^{-2}(2)^{4} = \dfrac{(2)^4}{(-3)^2}

Comparing the rightmost term with the second term in the question,

<em>a</em> = 4, <em>b</em> = 2

Solving on,

\dfrac{(2)^4}{(-3)^2} = \dfrac{(2)\times(2)\times(2)\times(2)}{(-3)\times(-3)} = \dfrac{16}{9}

Comparing with the final term in the question,

<em>c</em> = 16 and <em>d</em> = 9

Therefore,

<em>a</em> = 4, <em>b</em> = 2, <em>c</em> = 16, <em>d</em> = 9

3 0
2 years ago
Read 2 more answers
Nick billups is paid a salary of $ 900 a month, a 2 % commission on all sales, and 1.8 % more on monthly sales over $ 17,500. In
Trava [24]
June :
900 + 0.02(48,500) + 0.018(48500 - 17500) = 
900 + 970 + 558 = 2428 <==

July :
900 + .02(50,200) + 0.018(50200 - 17500) =
900 + 1004 + 588.60 = 2492.60 <===
5 0
2 years ago
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A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep
kupik [55]

Answer:

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option.

The final value for option 2=$32,800

Step-by-step explanation:

Option 1

New Zoomba for 60000 with a depreciation rat of 2%per month for 3 years

Exponential equation;

y=a(1-r)^t

where;

y=future value

a=initial value=60000

r=depreciation rate=2% per month

t=time interval=12×3=36 months

Replacing;

y=60000(1-2/100)^36

y=60000(0.98)^36=28,992.79

The value after 3 years=$28,992.79

Initial value-Final value=(60000-28992.79)=$31007.21

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(31007.21/60000)×100=51.68%

Option 2

New starfish for $40,000 with a depreciation of $200 per month for 3 years

Linear equation;

y=a-bt

where;

y=Future value

a=Initial value=$40,000

b=the depreciation amount per time interval=$200 per month for 3 years

t=time interval=(3×12)=36 months

Replacing;

y=40000-(200×36)

y=32,800

Final value=y=$32,800

Initial value-Final value=(40000-32800)=$7200

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(7200/40000)×100=18%

Option 1(51.68%)>Option 2(18%) therefor Option 1 loses value at a faster rate than Option 2

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option

4 0
2 years ago
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