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Dima020 [189]
2 years ago
13

Ariana and Emily are both standing in line at Papa Joe’s Pizza. Ariana orders 4 large cheese pizzas and 1 order of breadsticks.

Her total before tax is $34.46. Emily orders 2 large cheese pizzas and 1 order of breadsticks. Her total before tax is $18.48. Determine the cost of 1 large cheese pizza and 1 order of breadsticks. Explain the method you used for solving this problem.
Mathematics
1 answer:
Eva8 [605]2 years ago
6 0

The cost of 1 large pizza is $7.99 and cost of one breadstick is $2.50

Elimination method was used.

Step-by-step explanation:

Let,

Cost of one large pizza = x

Cost of one breadstick = y

According to given statement;

4x+y=34.46    Eqn 1

2x+y=18.48     Eqn 2

Subtracting Eqn 2 from Eqn 1

(4x+y)-(2x+y)=34.46-18.48\\4x+y-2x-y=15.98\\2x=15.98

Dividing both sides by 2

\frac{2x}{2}=\frac{15.98}\\x=7.99

Putting x=7.99 in Eqn 2

4(7.99)+y=34.46\\31.96+y=34.46\\y=34.46-31.96\\y=2.50

The cost of 1 large pizza is $7.99 and cost of one breadstick is $2.50

Elimination method was used.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/2131336
  • brainly.com/question/2150928

#LearnwithBrainly

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Find the hcf of 144 and 180. if it is expressed in the form 13m-3, find the value of m​
BaLLatris [955]

Answer:

Step-by-step explanation:

To find the HCF of 144 and 180

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in term of m

m=36

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To find m

Substitute for m when m=36

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2 years ago
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A cardboard box without a lid is to have a volume of 16,384 cm3. Find the dimensions that minimize the amount of cardboard used.
Reika [66]

Answer:

The dimensions that minimize the amount of cardboard used is

x = 31 cm ,  y = 34 cm & Z = 15.54 cm

Step-by-step explanation:

Volume of the cardboard = 16,384 cm^{3}

The function that represents the area of the cardboard without a lid is given by

f (x,y,z) = xy + 2xz + 2yz ------  (1)

Volume of the cardboard with sides x, y & z is

xyz = 16384

z =  \frac{16384}{xy}

Put this value of z in equation (1) we get

f (x,y,z) = xy + 2x(\frac{16384}{xy} ) + 2y(\frac{16384}{xy} )

f (x,y,z) = xy + \frac{32768}{y}  + 2y(\frac{32768}{x} )

Differentiate above equation with respect to x & y we get

f_{x}  = y - \frac{32768}{x^{2} }

f_{y}  = x - \frac{32768}{y^{2} }

Take f_{x}  = 0 \ and  \ f_{y} = 0

y - \frac{32768}{x^{2} } = 0

y = 32768 \ x^{-2}  ------ (2)

x - \frac{32768}{y^{2} } = 0

x = 32768 \ y^{-2}  ------- (3)

By solving equation (2) & (3) we get

x^{3} = 32768

x = 31 cm

From equation 2

y = 32768 \ x^{-2}

y = 32768 (31^{-2})

y = 34 cm

z =  \frac{16384}{xy}

z =  \frac{16384}{(34)(31)}

Z = 15.54 cm

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Members of the pep club were selling raffle tickets for $1.50 and $5. The number of $1.50 tickets sold was two less than four ti
marysya [2.9K]

Answer:

see below

Step-by-step explanation:

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Now we need to find the number of 1.50 tickets

Which equation can be used to determine how many $1.50 raffle tickets were sold?

x = 4y – 2

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