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Dima020 [189]
2 years ago
13

Ariana and Emily are both standing in line at Papa Joe’s Pizza. Ariana orders 4 large cheese pizzas and 1 order of breadsticks.

Her total before tax is $34.46. Emily orders 2 large cheese pizzas and 1 order of breadsticks. Her total before tax is $18.48. Determine the cost of 1 large cheese pizza and 1 order of breadsticks. Explain the method you used for solving this problem.
Mathematics
1 answer:
Eva8 [605]2 years ago
6 0

The cost of 1 large pizza is $7.99 and cost of one breadstick is $2.50

Elimination method was used.

Step-by-step explanation:

Let,

Cost of one large pizza = x

Cost of one breadstick = y

According to given statement;

4x+y=34.46    Eqn 1

2x+y=18.48     Eqn 2

Subtracting Eqn 2 from Eqn 1

(4x+y)-(2x+y)=34.46-18.48\\4x+y-2x-y=15.98\\2x=15.98

Dividing both sides by 2

\frac{2x}{2}=\frac{15.98}\\x=7.99

Putting x=7.99 in Eqn 2

4(7.99)+y=34.46\\31.96+y=34.46\\y=34.46-31.96\\y=2.50

The cost of 1 large pizza is $7.99 and cost of one breadstick is $2.50

Elimination method was used.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/2131336
  • brainly.com/question/2150928

#LearnwithBrainly

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To make the same totem pole with wood that costs y dollars Ronald would have to spend a total of $35.19. Explain which property
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Part 1) Subtraction Property of Equality

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we know that

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Researchers recorded that a group of bacteria grew from 100 to 7,000 in 14 hours. At this rate of growth, how many bacteria will
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6 0
2 years ago
Read 2 more answers
Research reports indicate that surveillance cameras at major intersections dramatically reduce the number of drivers who barrel
Tju [1.3M]

Answer:

(a)Increasing

(b)t=1.34 years

(c)16 cameras per year

Step-by-step explanation:

Given the function

N(t) = 5.85t³-23.43t²+45.06t+69.5, 0≤t≤4

(a)N(0)=5.85(0)³-23.43(0)²+45.06(0)+69.5=69.5

N(4)=5.85(4)³-23.43(4)²+45.06(4)+69.5=249.26

A function is increasing whenever x₁≤x₂, f(x₁)≤f(x₂).

Since in the interval (0,4), N(0)<N(4), we say the function is increasing.

(b)The number of communities using surveillance cameras at intersections changed least rapidly at the point where the derivative of the function is zero.

N(t) = 5.85t³-23.43t²+45.06t+69.5

N'(t)=17.49t²-46.86t+45.06

If N'(t)=0,

17.49t²-46.86t+45.06=0

Solving the quadratic equation gives the values of t as:

t=1.3396-0.8842i

t=1.3396+0.8842i

We take the Real Part as our Minimum value,

The time when number of communities using surveillance cameras at intersections changed least rapidly is:

t=1.34(to 2 decimal places)

(c)Rate of Increase using a security camera/year.

N'(t)=17.49t²-46.86t+45.06

N'(t)=17.49(1)²-46.86(1)+45.06

=15.69

≈16 cameras/year

7 0
2 years ago
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