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Gelneren [198K]
2 years ago
15

A coat at a store is originally priced at 54.99.The store marks the price down to 32.99.To the nearest percent ,what is the perc

ent markdown of the coat ?
Mathematics
1 answer:
AnnZ [28]2 years ago
7 0
For this case what we can do is the following rule of three:
 54.99 ------> 100%
 32.99 ------> x
 We clear the value of
 x = (32.99 / 54.99) * (100)
 x = 59.99272595
 Therefore, the discount percentage is:
 100-59.99272595 = 40.00727405%
 To the nearest percent;
 40%
 Answer:
 
The percent markdown of the coat is:
 
40%
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Each vertical cross-section of the triangular prism shown below is an isosceles triangle.
vova2212 [387]

Answer:

Height is 3

Step-by-step explanation:

4.24 x 4.24 x 6

Right triangle base = a + b + c

                         a^2 + 3^2  =  4.24^2

= a^2 + 9                             = 17.98

We cross out b to subtract.

                                   a^2  = 17.98 - 9

                                    a^2 = 8.98

We then square         √a^2 = √8.98

                                    a = 2.996

We round up               a = 3                                

We have found the height is 3

5 0
2 years ago
The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in theratio is 10, what is the Second numb
Zanzabum

Answer:

10:40

Step-by-step explanation:

As the left number increases by 1, the right number increases by 4. So as you can see, the left numbers go 3-4-5 while the right numbers go 12-16-20. So the answer is 10:40 because 10x4=40.

6 0
2 years ago
Read 2 more answers
After the price of petroleum oil went up by 10%, a consumer reduced his oil consumption by the same percent. By what percent wou
IgorLugansk [536]
Let's assign some random values to it, and say 1 unit of petroleum costs 100 bitcoins, because we all know bitcoins are the best currency :P

If the price goes up by 10%, it is now 100*1.1 = 110bitcoins for 1 unit.

However he's only getting 0.9 units now, so multiplying 110 by 0.9 gives us 99 bitcoins. His petroleum bill used to be 100 (which is why I picked 100 as it's easier), and now it is 99. Therefore his petroleum bill has reduced by 1%
7 0
2 years ago
Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is not even
mylen [45]
Well since the pattern is odd, even, odd, even you are just as likley to pull on odd (<span>not evenly divisible by 2) numebr as an even number, so the option is C.

Thank you for letting me answer your question here on brainly. I like to help people as much as I can, so please let me now if my answers provide any help to you. It means a lot to me to know that my questions help provide support to people in the community to need help. If you want extra help, you can PM me! I get lot of PMs tough, so it might take a while to respond, my apologies. Thanks for reading this, and have a great day! ~ brainily user, Lillyxrose
</span>
5 0
2 years ago
Read 2 more answers
Suppose the clean water of a stream flows into Lake Alpha, then into Lake Beta, and then further downstream. The in and out flow
Gala2k [10]

Answer:

a) dx / dt = - x / 800

b) x = 500*e^(-0.00125*t)

c) dy/dt = x / 800 - y / 200

d) y(t) = 0.625*e^(-0.00125*t)*( 1  - e^(-4*t) )

Step-by-step explanation:

Given:

- Out-flow water after crash from Lake Alpha = 500 liters/h

- Inflow water after crash into lake beta = 500 liters/h

- Initial amount of Kool-Aid in lake Alpha is = 500 kg

- Initial amount of water in Lake Alpha is = 400,000 L

- Initial amount of water in Lake Beta is = 100,000 L

Find:

a) let x be the amount of Kool-Aid, in kilograms, in Lake Alpha t hours after the crash. find a formula for the rate of change in the amount of Kool-Aid, dx/dt, in terms of the amount of Kool-Aid in the lake x:

b) find a formula for the amount of Kook-Aid in kilograms, in Lake Alpha t hours after the crash

c) Let y be the amount of Kool-Aid, in kilograms, in Lake Beta t hours after the crash. Find a formula for the rate of change in the amount of Kool-Aid, dy/dt, in terms of the amounts x,y.

d) Find a formula for the amount of Kool-Aid in Lake Beta t hours after the crash.

Solution:

- We will investigate Lake Alpha first. The rate of flow in after crash in lake alpha is zero. The flow out can be determined:

                              dx / dt = concentration*flow

                              dx / dt = - ( x / 400,000)*( 500 L / hr )

                              dx / dt = - x / 800

- Now we will solve the differential Eq formed:

Separate variables:

                              dx / x = -dt / 800

Integrate:

                             Ln | x | = - t / 800 + C

- We know that at t = 0, truck crashed hence, x(0) = 500.

                             Ln | 500 | = - 0 / 800 + C

                                  C = Ln | 500 |

- The solution to the differential equation is:

                             Ln | x | = -t/800 + Ln | 500 |

                                x = 500*e^(-0.00125*t)

- Now for Lake Beta. We will consider the rate of flow in which is equivalent to rate of flow out of Lake Alpha. We can set up the ODE as:

                  conc. Flow in = x / 800

                  conc. Flow out = (y / 100,000)*( 500 L / hr ) = y / 200

                  dy/dt = con.Flow_in - conc.Flow_out

                  dy/dt = x / 800 - y / 200

- Now replace x with the solution of ODE for Lake Alpha:

                  dy/dt = 500*e^(-0.00125*t)/ 800 - y / 200

                  dy/dt = 0.625*e^(-0.00125*t)- y / 200

- Express the form:

                               y' + P(t)*y = Q(t)

                      y' + 0.005*y = 0.625*e^(-0.00125*t)

- Find the integrating factor:

                     u(t) = e^(P(t)) = e^(0.005*t)

- Use the form:

                    ( u(t) . y(t) )' = u(t) . Q(t)

- Plug in the terms:

                     e^(0.005*t) * y(t) = 0.625*e^(0.00375*t) + C

                               y(t) = 0.625*e^(-0.00125*t) + C*e^(-0.005*t)

- Initial conditions are: t = 0, y = 0:

                              0 = 0.625 + C

                              C = - 0.625

Hence,

                              y(t) = 0.625*( e^(-0.00125*t)  - e^(-0.005*t) )

                             y(t) = 0.625*e^(-0.00125*t)*( 1  - e^(-4*t) )

6 0
2 years ago
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