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2 years ago

Melissa got two puppies, Ben and Sadie.

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

7 0

Answer:

x = 4y - 20

Step-by-step explanation:

x = Sadie's weight

y = Ben's weight

x = 4(y - 5)

x = 4y - 20

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Celina can walk 4 miles in 1 hour and can run 8 miles in 1 hour. What percent of Celina’s average running speed is her average w

Valentin [98]

Okay. So, we're looking for the percentage of Celina's running speed as her walking speed. Her running sped is 8 mph and her walking speed is 4mph. All we have to do is 4/8 = x/100. You put change/original and x/100, because we're looking for the percent of change from running speed to walking speed. Cross multiply the values to get 400 = 8x. Divide each side by 8 to isolate the "x". 400/8 is 50. x = 50. Celina's walking speed is 50% of her running speed. The answer is B: 50%.

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2 years ago

Write 11,760,825 in word form and expanded form

tankabanditka [31]

11,000,000 + 700,000 + 60,000 + 800 + 20 + 5 (expanded form)

eleven million seven hundred sixty thousand eight hundred twenty-five (word form)

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2 years ago

If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?

Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are $c(x) = \frac{5}{x - 2}$ and d(x) = x + 3

So, (cd)(x) = $(\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}$

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

8 0

2 years ago

Read 2 more answers

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us

grigory [225]

Answer:

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n represent the sample size

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

5 0

2 years ago

A region R in the xy-plane is given. Find equations for a transformation T that maps a rectangular region S in the uv-plane onto

Gre4nikov [31]

$\begin{cases}y=2x-2\\y=2x+2\end{cases}\implies\begin{cases}-2x+y=-2\\-2x+y=2\end{cases}$

For these lines, let $u=-2x+y$ .

$\begin{cases}y=2-x\\y=4-x\end{cases}\implies\begin{cases}x+y=2\\x+y=4\end{cases}$

And for these, let $v=x+y$ .

Now,

$\begin{cases}u=-2x+y\\v=x+y\end{cases}\implies \begin{bmatrix}u\\v\end{bmatrix}=\underbrace{\begin{bmatrix}-2&1\\1&1\end{bmatrix}}_{\mathbf T}\begin{bmatrix}x\\y\end{bmatrix}$

The vertices of $S$ in the x-y plane are (0, 2), (2/3, 10/3), (2, 2), and (4/3, 2/3). Applying $\mathbf T$ to each of these yields, respectively, (2, 2), (2, 4), (-2, 4), and (-2, 2), which are the vertices of a rectangle whose sides are parallel to the u-v plane.

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2 years ago