T is a linear function of C ==> T = mC + b
Each additional chirp C corresponds to an increase in T of 0.25 ==> m = 0.25
T = 52 when C = 20 ==> 52 = 0.25(20) + b ==> b = 52 - 5 = 47
So T = 0.25C + 47
When C = 100 then T = 0.25(100) + 47 = 25 + 47 = 72
When C = 120 then T = 0.25(120) + 47 = 30 + 47 = 77 so the
temperature range is between 72 and 77 when there are between 100 and
120 chirps per minute
Answer:
y2 = m(x2-x1)+y1
Step-by-step explanation:
Given the formula for finding the slope of a linear equation to be;
m = y2-y1/x2-x1 where x and y are from the ordered pairs (x1,y1) and (x2,y2)
To get the equivalent equation for y2, we will make y2 the subject of tbw formula from the equation as shown:
m = y2-y1/x2-x1
Cross multiplying
m(x2-x1) = y2-y1
mx2-mx1 = y2-y1
Adding y1 to both sides of the equation we have;
mx2-mx1 + y1= y2-y1+y1
y2 = mx2-mx1 + y1
y2 = m(x2-x1)+y1
This gives the resulting equation to solve for y2
Answer:
A.
Step-by-step explanation:
we are going from a large shape to a smaller shape. the proof is that the side lengths go down from 7m to 0.5m. so, it is a reduction.
and the scaling factor s ? what do we need to multiply the original side lengths with to get the new ones ?
7 × s = 0.5 = 1/2
s = (1/2)/7 = (1/2)/(7/1) = (1×1)/(2×7) = 1/14
=> answer A is correct
Scale factor is 9/15 or 3/5 in simplest form, and I think x would equal 10.
Answer:
3.28 x 10^-4
Step-by-step explanation:
0.000328 = 3.28 x 10^-4