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NNADVOKAT [17]
2 years ago
5

Use the expression below to complete the following tasks. (3a2 - 5ab + b2) - (-3a2 + 2b2 + 8ab) What is the additive inverse of

the polynomial being subtracted?
Mathematics
2 answers:
Ket [755]2 years ago
7 0

Answer:

1) C    2)C   3) B

Step-by-step explanation:

Just Got it Right People.

Basile [38]2 years ago
6 0
Remember that the additive inverse are two equal numbers (or expressions) but with different signs.
 We have then, that according with the coment below:
 (3a2 - 5ab + b2) - (-3a2 + 2b2 + 8ab)
 the additive inverse is:
 (3a2 - 2b2 - 8ab) Note that is the same expression that
 (-3a2 + 2b2 + 8ab)
 but with different signs.
 Answer:
 the additive inverse of the polynomial being subtracted is 
 (3a2 - 2b2 - 8ab)
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a computer shop charges 20 pesos per hour (or a fraction of an hour) for the first two hours and additional 10 pesos per hour fo
Serhud [2]

Answer:

The equation for the price, as a function of time in hours is:

P(x) = 20*x    for 0 ≤ x ≤ 2

P(x) = 40 + 10*(x - 2)  for  2 ≤ x

Now, we want to evaluate this function in 40 mins.

we know that 1 hour = 60mins.

Then 40 mins = (40/60) hours = 0.67 hours.

Then we input this in our function, and because this is smaller than 2, we use the first piece of our function:

P(0.67) = 20*0.67 = 13.4

So in 40 mins, the charge will be 13.4 pesos.

7 0
2 years ago
Harvie buys one notebook for $1. 59 and pens for $0. 29 each. He spends a total of $5.07 Assume there is
Andre45 [30]

Answer:

0.29p + 1.59 = 5.07 where p represents the number of pens

Step-by-step explanation:

5 0
2 years ago
Janice works at a cell phone company. She wants to make a presentation to her team about the features of a new phone. She makes
Advocard [28]
If 1 inch represents 0.5 centimeter, then 28 inches will represent 28 * 0.5 = 14 centimeters and 15 inches will represent 15 * 0.5 = 7.5 centimeters.

The actual dimensions of the phone is: the length is 14 centimeters and the width is 7.5 centimeters.
8 0
2 years ago
Read 2 more answers
What is a3 in an arithmetic sequence in which a10=41 and a15=61
USPshnik [31]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_{10}&41\\
a_{11}&41+d\\
a_{12}&(41+d)+d\\
&41+2d\\
a_{13}&(41+2d)+d\\
&41+3d\\
a_{14}&(41+3d)+d\\
&41+4d\\
a_{15}&(41+4d)+d\\
&41+5d=61
\end{array}
\\\\\\
41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\
-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=10\\
a_{10}=41
\end{cases}
\\\\\\
41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

thus

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=3\\
a_{1}=5
\end{cases}
\\\\\\
a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and surely you know how much that is.
8 0
2 years ago
Read 2 more answers
Train A and train B stops at Swindon at 10:30 . Train A stops every twelve minutes and train B stops every 14 Mins , when do the
Nata [24]

Answer: at 11:54

Step-by-step explanation:

Let's define the 10:30 as our t = 0 min.

We know that Train A stops every 12 mins, and Train B stops every 14 mins, they will stop at the same time in the least common multiple of 12 and 14.

To find the least common multiple of two numbers, we must do:

LCM(a,b) = a*b/GCD(a,b)

Where GCD(a, b) is the greatest common divisor of a and b.

In this case the only common divisior of 12 and 14 is 2.

So we have:

LCM(12, 14) = 12*14/2 = 84.

Then the both trains will stop 84 minutes after 10:30

one hour has 60 mins, so we can write 84 minutes as:

1 hour and 24 minutes = 1:24

Then they will stop at the same time at 10:30 + 1:24 = 11:54

4 0
2 years ago
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