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2 years ago

Three times the sum of half Carlita's age and 3 is at least 12. What values represent Carlita's possible age?

Mathematics

2 answers:

a_sh-v [17]2 years ago

7 0

Answer:

Carlita is at least 2 years old

Step-by-step explanation:

Let x = Carlita's age

3[(1/2)x + 3] ≥ 12 Divide both sides by 3.

(1/2)x + 3 ≥ 4

(1/2)x ≥ 1

x ≥ 2

cestrela7 [59]2 years ago

5 0

Answer:

at least 6

Step-by-step explanation:

3(.5x+3)>12

1.5x+9>12

1.5>9

x>6

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mestny [16]

Peyton is 28 years old

Justin is 7 years old

Matt is 4 years old

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2 years ago

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One hundred teachers attended a seminar on mathematical problem solving. The attitudes of representative sample of 12 of the tea

andrew11 [14]

Answer:

a) 1.92

b) 3.25

c) 1.5

d) -5.23

Step-by-step explanation:

We are given the following in the question:

4, 7, -1, 1, 0, 5, -2, 2, -1, 6, 5, -3

a) mean of score change

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{23}{12} = 1.92$

b) standard deviation for this population

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

Sum of squares of differences = 126.92

$\sigma = \sqrt{\frac{126.92}{12}} = 3.25$

c) median change score

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted data: -3, -2, -1, -1, 0, 1, 2, 4, 5, 5, 6, 7

Median =

$\dfrac{6^{th} + 7^{th}}{2} = \dfrac{1+2}{2} = 1.5$

d) change score that is 2.2 standard deviations below the mean.

$x = \mu - 2.2(\sigma)\\x = 1.92-2.2(3.25)\\x = -5.23$

4 0

2 years ago

June made a design with 6 equal tiles.One tile is yellow 2 tiles are blue and 3 tiles are purple. what fraction of the tiles are

lana66690 [7]

we know that

The fraction of each tile color can be found by dividing the number of tiles for each tile by the total number of tiles, then simplifying the fraction if possible.

Let

N----------> total number of tiles

Y---------> number of yellow tiles

B--------> number of blue tiles

P--------> number of purple tiles

we have

$N=6\\ Y=1\\ B=2\\ P=3$

1) Find the fraction of yellow tiles

we know that

the fraction of yellow tiles is equal to

$Y/N$

substitute the values

$1/6$

2) Find the fraction of purple tiles

we know that

the fraction of purple tiles is equal to

$P/N$

substitute the values

$3/6$

3) Find the fraction of yellow tiles or purple tiles

we know that

the fraction of yellow tiles or purple tiles is equal to

$(Y/N)+(P/N)=(1/6)+(3/6)=4/6=2/3$

therefore

the answer is

$2/3$

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2 years ago

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HELP I WILL NAME YOU BRAINLIEST!! Given: Circumscribed polygon ACEG B, H, F, D -points of tangency AB=5, CD=4, DE=3, FG=2 Find:

wolverine [178]

Answer:

perimeter = 28

Step-by-step explanation:

Tangents drawn to a circle from an external point are congruent, thus

AH = AB = 5

GH = GF = 2

EF = ED = 3

CB = CD = 4

Sum the 8 parts for perimeter of polygon ACEG

perimeter = 5 + 5 + 2 + 2 + 3 + 3 + 4 + 4 = 28

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2 years ago

A sample of an unknown chemical element naturally loses its mass over time. The relationship between the elapsed time ttt, in mo

Naddik [55]

Answer:

Step-by-step explanation:

Given a sample M(t)

M(t) = 120 • ( 81 / 625)^t

When is the fraction of the mass decay to 3/5 of it's mass

Generally

M(t) = Mo•(k^t)

The original mass is 120

Mo = 120

So, we want to find time when it decay to 3/5 of it's original mas

M = 3/5 × 120

M = 72

Then,

M(t) = 120 • ( 81 / 625)^t

72 = 120 • ( 81 / 625)^t

72 / 120 = ( 81 / 625)^t

0.6 = ( 81 / 625)^t

Take natural logarithmic of both sides

In(0.6) = In(81/625)^t

In(0.6) = t•In(81/625)

t = In(0.6) / In(81/625)

t = In(0.6) / In(0.1296)

t = 0.25 monthly

t = ¼ monthly

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2 years ago