Answer:
a. We reject the null hypothesis at the significance level of 0.05
b. The p-value is zero for practical applications
c. (-0.0225, -0.0375)
Step-by-step explanation:
Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.
Then we have 
, 
, 
and 
, 
, 
. The pooled estimate is given by
a. We want to test 
vs 
(two-tailed alternative).
The test statistic is 
and the observed value is 
. T has a Student's t distribution with 20 + 25 - 2 = 43 df.
The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value 
falls inside RR, we reject the null hypothesis at the significance level of 0.05
b. The p-value for this test is given by 
0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.
c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)
, i.e.,
where 
is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So
, i.e.,
(-0.0225, -0.0375)
Position in the sequence triangular number relation
1 1 1 = 1*(1+1)/2
2 3 3 = 2(2+1)/2
3 6 6 = 3(3+1)/2
4 10 10 = 4(4+1)/2
5 15 15= 5(5+1)/2
Call n the position in the sequence, then the triangular number is: n(n+1)/2
Answer:
The value of y is -5
Step-by-step explanation:
we have
------> equation A
------> equation B
we know that
If x and y satisfy both equations, then (x,y) is the solution of the system of equations
Using a graphing tool
Remember that
The solution of the systems of equations is the intersection point both graphs
The intersection point is (2,-5)
therefore
The solution of the system of equations is the point (2,-5)
The value of y is -5
We are given the inequality x < -2 or x ≥ 3 in which the problem asks to determine the domain of the inequality. In this case, this means numbers less than -2 or numbers equal to 3 and greater than three. The relation that illustrates the previous statement is B. x e(-∞,-2) n[3,∞)
