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Leni [432]
2 years ago
5

Yesterday, two friends went into a bank to open savings accounts. Allie started by putting $783 in her account, and she will dep

osit an additional $27 each week. Nick made no initial deposit, but he will add $288 more each week. In a few weeks, the friends will have the same account balance. What is that account balance? How many weeks will that take?
Mathematics
1 answer:
posledela2 years ago
4 0

<u>Answer:</u>

Both accounts of Nick and Allie will have same amount of $864 in time period of 4 weeks.

<u>Solution: </u>

Given, Yesterday two friends went into a bank to open savings accounts.  

Allie started by putting $783 in her account, and she will deposit an additional $27 each week.  

Nick made no initial deposit, but he will add $288 more each week.  

In a few weeks, the friends will have the same account balance.  

Here, account balance of Allie for every week forms an A.P as

783, 810, 837, ……. With common difference 27

And, account balance of nick for every week will be  

0, 288, 576, …….. with common difference 288

Let, after n weeks the balance in both accounts be equal.

Then, nth term of both series will be equal, we know that, nth term tn of A.P is a + (n – 1)d  

Where, a is first term, d is common difference and n is number of terms.

Now, nth term of allie series = nth term of nick series.

783 + (n – 1) x 27 = 0 + (n – 1) x 288  

Here, we used same n for both sides because n represents number of weeks and it is common to both

783 + 27n – 27 = 288n – 288

756 + 288 = 288n – 27n

261n = 1044

n = 4.

So, it will take 4 weeks to have same balance and now, substitute n value in nth term of nick series.

4 \text { th term }=0+(4-1) \times 288 \rightarrow 4^{\text {th }} \text { term }=3 \times 288=864

Hence, both accounts will have same amount of $864 in time period of 4 weeks

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I'd say Yana has 6...

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1 year ago
Let’s play Pick-A-Ball with replacement! There are 10 colored balls: 3 red, 4 white, and 3 blue. The balls have been placed into
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Answer:

0.48

Step-by-step explanation:

There are 10 colored balls: 3 red, 4 white, and 3 blue.

You selected 2 balls at random. They may be

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To find the probability of selecting the color of ball that you just selected, find this probability in each of previous cases:

RR: (One red ball left and 8 balls left in total)

P_{RR}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}

WW: (Two white balls left and 8 balls left in total)

P_{WW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{2}{8}=\dfrac{1}{30}

BB: (One blue ball left and 8 balls left in total)

P_{BB}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}

RW: (Two red and three white balls left and 8 balls left in total)

P_{RW}=\dfrac{3}{10}\cdot \dfrac{4}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

RB: (Two red and two blue balls left and 8 balls left in total)

P_{RB}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}

WB: (Two blue and three white balls left and 8 balls left in total)

P_{WB}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

WR: (Two red and three white balls left and 8 balls left in total)

P_{WR}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

BR: (Two red and two blue balls left and 8 balls left in total)

P_{BR}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}

BW: (Two blue and three white balls left and 8 balls left in total)

P_{BW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

In total, the probability of selecting the color of ball that you just selected is

\dfrac{1}{120}+\dfrac{1}{30}+\dfrac{1}{120}+2\cdot\dfrac{1}{12}+2\cdot \dfrac{1}{20}+2\cdot \dfrac{1}{12}=\\ \\=\dfrac{1}{120}+\dfrac{4}{120}+\dfrac{1}{120}+\dfrac{20}{120}+\dfrac{12}{120}+\dfrac{20}{120}=\dfrac{58}{120}=\dfrac{29}{60}\approx 0.48

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Given: Annual income earned by Lenny = \$58,475

Passive income =  \$1,255

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Now,  \text{Total gross income =Annual income+Passive income+Capital gain}

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Hence, Lenny's total gross income for the year = $62,080

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