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sveta [45]
1 year ago
12

When Hiroto is writing, there is 0.92 probability that there will be no spelling mistakes on a page. One day, Hiroto writes an e

ssay that is 11 pages long.
Assuming that Hiroto is equally likely to have a spelling mistake on each of the 11 pages, what is the probability that he will have a spelling mistake on at least one of the pages?
Mathematics
1 answer:
prohojiy [21]1 year ago
8 0

Answer:

0.60

Step-by-step explanation:

Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

The probability of a mistake on at least one page is 1 minus the probability of making no mistakes.

P(at least 1) = 1 − P(none)

P = 1 − ₁₁C₀ (0.08)⁰ (0.92)¹¹⁻⁰

P = 1 − (0.92)¹¹

P = 0.60

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user100 [1]

Answer:

26

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5 0
1 year ago
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
yaroslaw [1]

Answer:

The statement provided is True.

Step-by-step explanation:

The exponential function representing growth is given as follows:

y=y_{0}\cdot e^{kt}

Here,

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7 0
1 year ago
 how do i slove  5/9v+w=z, for v
nekit [7.7K]
Okay, let's do this~

we want v isolated on one side so let's bring w over through subtraction

now we have 5/9v=z-w

now, to get rid of that fraction attached to v, we will multiply it's reciprocal on both sides.

*the reciprocal of 5/9 is 9/5

(5/9) x (9/5) cancel each other leaving v isolated to the left

the other side should look like this 9/5(z-w)

now we put both parts together to end up with:

v= 9/5(z-w)

there you go! :D

 
3 0
1 year ago
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