A sample of 75 concrete blocks had a mean mass of 38.3 kg with a standard deviation of 0.6 kg.

If a plant grows 1/4 cm every day for 21 days, what is the total amount of growth?

Naddika [18.5K]

I think it’s 5.25 cm but you might want to double check.

5 0

2 years ago

240 people are going to a charity event 3/5 of the guests have ordered chicken for their meals of the remaining guests 12.5% hav

Yuri [45]

Answer: 84 people

Step-by-step explanation:

From the question, 240 people are going to a charity event and 3/5 of the guests have ordered chicken for their meals. This means (3/5 × 240) = 144 people ordered chicken. Since 144 people have ordered, the number of remain people left will be:

= 240 - 144

= 96 people.

Out of the remaining guests which is 96, 12.5% have ordered gluten free meals. This means (12.5% × 96) = 12 ordered gluten free meals.

The people who haven't ordered their meals yet will be:

= 96 - 12

= 84 people.

6 0

2 years ago

Find the volume of the composite space figure to the nearest whole number.

Alika [10]

Figure 1:
3 x 8 x 5 = 120cm³

Figure 2:
2 x 5 x 6 = 60cm³

Total Volume = 120 + 60 = 180cm³

3 0

2 years ago

Read 2 more answers

Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1

astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

$x^{2} - 24 = 1$

Given that resulting expression is a second order polynomial of the form $x^{2} - a^{2}$ , there are two real and distinct solutions. Roots of the expression are:

$x_{1} = -5$ and $x_{2} = 5$ .

Now, it is also required to determine which part of the interval $(x_{1}, x_{2})$ is equal to a number greater than zero (positive). That is:

$x^{2} - 24 > 0$

$x^{2} > 24$

$x < -4.899$ and $x > 4.899$ .

Therefore, exists two sub-intervals: $[-5, -4.899]$ and $\left[4.899,5\right]$ . Besides, $x^{2} - 24 > y = 1$ in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

$A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx$

$A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx$

$A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}$