Answer:
9
Step-by-step explanation:
total is 30
spent is $9
this is total money minus the amount of the picture frame
30-9
21 divide by 3
the total sum of journals bought was 9
Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
A stop sign has a total of 8 sides measuring 12.4 inches on
each side and 30 inches for the distance of each sides.
Given the measurement, the rectangle's dimensions are as
follows:
If divided horizontally: Length = 12.4 inches, width = 30
inches
If divided vertically: Length = 30 inches, width = 12.4
inches
From the divided rectangle, we can produce a 3-side equal
trapezoid. In this case, we will have a uniform measurement of 12.4 inches on
each side and 30 inches for the longer side.
One rose is 50 cents, so 2 roses cost $1 ( 50 cents x 2).
2 roses per dollar x 20 dollars = 40 total roses sold.
When they sell $20 dollars they make $6, so that means they pay 20-6 = $14 dollars for the 40 roses.
$14 / 40 roses = 0.35 per rose.
She pays 35 cents per rose.
T= total
<span>Money spent is: </span>
48+ 1/3 (T-48) = 1/2 T
One equation for one unknown, solve:
48 + 1/3 T -1/3*48= 1/2 T
48 - 16 =1/2 T- 1/3 T
32= 1/6 T
T= 6*32
<span>T=192
</span>192-48=144 money left after watch
1/3*144=48 third of leftover, spent on pen
<span>144-48=96 left which is half of 192. </span>
