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forsale [732]
2 years ago
8

Huixian mother buys some shares of company A on day 0. on day 7, the share price of company a is $4.60. if she sells all her sha

res pf company A and buys 2000 shares of company B on day 7, she would receive $7400. on day 12, the share price of company A is $4.80 and the share price of company B is $0.50 less than that on day 7
If she sells all her shares of company A and buys 5000 shares of company B on day 12, she would have to pay $5800. find
a. the number of shares of company A huixian mother has.
b. the share price of company B on day 12
Mathematics
1 answer:
Wewaii [24]2 years ago
4 0
I think that u might want to do the share the company money i could be wrong but if i sm sorry

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Look at Andrea’s running journal.
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What is the true solution to the equation below?
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Answer:

Step-by-step explanation:

some rules of logarithmic function

ln(a) - ln(b)=ln(\frac{a}{b})

e^{ln(a)}=a

ln(a)^{n}=nln(a) vice-versa nln(a)=ln(a)^{n}

If ㏑(a) = ㏑(b), then a = b

∴ 2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)

Use the 2nd rule to simplify it

e^{ln(2x)}=2x\\e^{ln(10x)}=10x\\

2㏑(2x) - ㏑(10x) = ㏑(30)

Use the 3rd rule in the 1st term

∵ 2㏑(2x) = ㏑(2x)² = ㏑(4x²)

∴ ㏑(4x²) - ㏑(10x) = ㏑(30)

- Use the 1st rule with the left hand side

ln(4x^{2})-ln(10x)=ln(\frac{4x^{2}}{10x})\\\\ln(\frac{4x^{2}}{10x})=ln(30)\\\\ \frac{4x^{2}}{10x}=\frac{2x}{5}=\frac{2}{5}x\\\\ ln(\frac{2}{5}x)=ln(30)

Use the 4th rule

\frac{2}{5} x = 30

Multiply both sides by 5

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- Divide both sides by 2

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The value of x = 75

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2 years ago
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Suppose that the concentration of a bacteria sample is 100000 bacteria per milliliter. If the concentration doubles every 2 hour
Aliun [14]

Answer:

3.85 hours

Step-by-step explanation:

We have that the model equation in this case would be of the following type, being "and" the concentration of bacteria:

y = a * e ^ (b * t)

where a and b are constants and t is time.

We know that when the time is 0, we know that there are 100,000 bacteria, therefore:

100000 = a * e ^ (b * 0)

100000 = a * 1

a = 100000

they tell us that when the time is 2 hours, the amount doubles, that is:

200000 = a * e ^ (b * 2)

already knowing that a equals 100,000

e ^ (b * 2) = 2

b * 2 = ln 2

b = (ln 2) / 2

b = 0.3465

Having the value of the constants, we will calculate the value of the time when there are 380000, that is:

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