Answer:
number of shells zoe gives to dev = 7
number of shells zoe is left with = 55-7= 48
number of shells dev has = 9+7=16
Step-by-step explanation:
let the initial number of shells that dev has be A, and initial number of shells that zoe has be B.
let the number of shells that zoe gives to dev be x.
after giiving x shells zoe is left with 3 times the number of shell as that of dev.
therefore number of shells with zoe = 3×number of shells with dev.
number of shells with zoe = initial shells - x = 55-x
number of shells with dev = initial shells + number of shells he gets
= 9+x
therefore (55-x)=3×(9+x)
55-x = 27+3x
55-27=3x+x
4x = 28
x= 7
therefore number of shells zoe gives to dev = 7
number of shells zoe is left with = 55-7= 48
number of shells dev has = 9+7=16
Answer:
error in step 1
Step-by-step explanation:
well where is does the step not make sense?
remember cos(pi) = -1 and sin(pi)=0
that means step 1 is strange... it didn't distribute properly
it should have been:
cos(pi) - cos(A)
hope that helps! ^-^
Answer:
Step-by-step explanation:
Andrew's favorite vegetables are cucumbers, green beans, and red peppers.
Samantha enjoyed many types of music; jazz, classical, hip hop, country, and heavy metal,
Correct me if I'm wrong
For the first investment. A = P(1 + rt); where p = 9,720, r = 0.0316 and t = 1/12
A = 9720(1 + 0.0316/12) = 9720(1.0026) = $9,746
For the second investment,
A = 8140(1 + 0.0323 x 2) = 8140(1.0646) = $8,666
Total amount she had = $9,746 + $8,666 = $18,412
Answer: The difference of 6 times a number m and 2
Step-by-step explanation:
The way to write this expression is:
The difference of 6 times a number m and 2.
