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1 year ago

Solve the system of linear equations by graphing. Round the solution to the nearest tenth.

Mathematics

2 answers:

Soloha48 [4]1 year ago

9 0

Answer: The correct answer is (1.2, 4.4).

hope this is helpful (:

jeyben [28]1 year ago

6 0

Answer:

The approximate solution to the system is (1.2, 4.4)

x = 1.2 and y = 4.4

Step-by-step explanation:

The solution of the system of linear equations equation y = –0.25x + 4.7 and y = 4.9x – 1.64 is shown in the attached graph. The red line represents the equation y = –0.25x + 4.7 and the blue line represents the equation = 4.9x – 1.64.

The solution of the system of equations is their point of intersection shown on the graph.

The point of intersection is (1.231, 4.392). To the nearest tenth, it is (1.2, 4,4). So x = 1.2 and y = 4.4.

So the approximate solution to the system is (1.2, 4.4)

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2 years ago

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2 years ago

Read 2 more answers

Town Hall is located 4.3 miles directly east of the middle school. The fire station is located 1.7 miles directly north of Town

Maksim231197 [3]

Answer:

2.1 miles

Step-by-step explanation:

you can see a drawing of the situation in the attached picture (you need to draw all the places mentioned and the distance between them),

this way we can form a right triangle between the school and the hospital with measures of sides: 1.7 and 1.2 miles

and the green line is the straight line between the school and the hospital, so you need pythagoras to find the value:

$\sqrt{1.7^2+1.2^2}\\=\sqrt{2.89+1.44}\\=\sqrt{4.33} \\ =2.081$

rounding to the nearest tenth:

2.1 miles

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2 years ago

A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb

Kobotan [32]

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

$0.55*S +0.59*G = 2,300\\0.45*S+0.41*G = 1,700$

Solving the linear system above:

$(0.55 *S +0.59*G)- \frac{0.55}{0.45} (0.45*S+0.41*G)= 2,300-\frac{0.55}{0.45}*1,700*\\0.088888*G = 222.222\\G=2,500\\S =\frac{2,300-2,500*0.59}{0.55}\\S=1500$