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2 years ago

Work the following problems using the table. Choose the correct answer.

Mathematics

1 answer:

kakasveta [241]2 years ago

5 0

Answer:

option 3

$46.02

Step-by-step explanation:

First we have to look at the value of the French francs with respect to the dollars, we will look at the option of Wednesday which is how the problem asks.

if we see in the table it tells us that every 1 french franc gives us 0.2301 dollars

Now if we have 200 French francs, how many dollars will they give us?

1 = 0.2301

200 = ?

200 * 0.2301 / 1 =

46.02

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Emily wants to hang a painting in a gallery. The painting and frame must have an area of 31 square feet. The painting is 5 feet

seropon [69]

Area=legnth times width=31
the frame must go around the frame with equal legnth, x
so
the total area (meaning the frame +picture) is 5+x by 6+x
31=(5+x)(6+x)
expand
31=30+11x+x^2
minus 31 both sides
0=-1+11x+x^2
x^2+11x-1=0

answer is third one

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2 years ago

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Which expression is the result of solving the equation ax - b = cy for 2? (For a + 0)

Masja [62]

I would say cy hopes this help

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2 years ago

Joanne has a goal of buying a townhome and saved for 5 years. She expected to have the down payment of $15,000 saved by now but

serg [7]

Answer:

Step-by-step explanation:

Average amount saved per year = $\frac{15,000}{5}$

=$ $3000$

So on average Joanne has saved $3000 per year. She only needs $2000 more which will not even take a year to save.

How many months it will take to save $2000:

$\frac{12}{3000} \times2000$

= $8$ Months.

It will only take Joanne 8 moths to save $2000.

If she really wants to buy the home now she can always go for a home loan scheme for $2000. Any interest rate less than 50% per year is fine as she can save $3000 per year.

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2 years ago

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Coordinates, gradient and tangent work (see image).

Ivenika [448]

Answer:

a) $P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)$

b) $4x+2h$

c) $4x$

Step-by-step explanation:

Given the curve

$y=2x^2-5$

a) If the x-coordinate of P is $x$ , then the y-coordinate is $2x^2-5,$ so point P has coordinates $(x,2x^2-5)$

If the x-coordinate of Q is $x+h$ , then the y-coordinate is $2(x+h)^2-5$ so point Q has coordinates $(x+h,2(x+h)^2-5)$

b) The gradient of the secant RQ is

$\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h$