The number 2*2*2*4*5 is not in its prime factorization because not all the factors are prime numbers. A prime number is a number that has no other factors except for 1 and itself.
4 is not a prime number, since it can be divided by 2. The number can be broken down into its prime factors by dividing by 2, and it becomes 2*2.
Therefore, the factorization of the number 2*2*2*4*5 can be broken down to 2*2*2*2*2*5.
Answer:
ai) n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) see attachment
bi) n(C⋂G) = x = 1
bii) n(G) only = 3
Step-by-step explanation:
Let chemistry = C
Economic = E
Government = G
n(E) = 12
n(G) = 8
n(C) = 7
ai) number of pupils for economics and chemistry = 0
number of pupils for economics and government = 4
The set notation for both:
n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) find attached the Venn diagram
bi) n(C⋂G) = ?
Let number of n(C⋂G) = x
From the Venn diagram
n(C) only = 12-4 = 8
n(G) only = 8-(4+x) = 4-x
n(E) only = 7-x
n(E⋂C⋂G) = 0
n(E⋂C) = 0
n(E⋂G) = 4
Total: 8+ 4-x + 7-x + x + 0+0+4 = 22
23 -x = 22
23-22 = x
x = 1
n(C⋂G) = x = 1
Number of pupils that take both chemistry and government = 1
(bii) government only = n(G) only = 4-x
n(G) only = 4-1 = 3
Number of students that take government only = 3
Answer:
2^27
Step-by-step explanation:
Given the following expression:
[(2^10)^3 x (2^-10)] ÷ 2^-7
This can be easily simplified. Let us simplify the numerator first. To do that, we have
(2^10)^3 making use of the power rule of indices that says:
(A^a)^b = A^ab where a and b are powers, we have:
2^(10x3) = 2^30
Therefore the numerator becomes:
2^30 x 2^-10. Also making use of the multiplication rule that says:
A^a x A^b = A^(a + b), we have
2^30 x 2^-10 = 2^(30 – 10) = 2^20.
Now we have:
(2^20) ÷ (2^-7)
To simplify this, we need the division rule of indices which says:
A^a ÷ A^b = A^(a – b)
Therefore we have:
(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27
Answer:
a) Narrower
b) Narrower
c) Wider
Step-by-step explanation:
We are given the following in the question:
Proportion of coworker who received flu vaccine = 32%
98% confidence interval: (0.231, 0.409)
Confidence interval:

a) Sample size had been 600 instead of 150
If we increase the sample size, thus the standard error of the interval decreases.
Since the standard error decreases, the confidence interval become narrower.
b) Confidence level had been 90% instead of 98%
As the confidence level increases, the confidence interval becomes narrower. This is due to a smaller value of z-statistic at 90% confidence level.
c) Confidence level had been 99% instead of 98%
As the confidence level increases, the width of the confidence interval increases and the confidence interval become wider. This is because of a larger value of z-statistic at 99% confidence interval.
Machine should abide by te following:
4.225<Machine<4.233 The margin of acceptance
:
4.233-4.225 = 0.008cm.
Any thickness greater than 4.233+0.008 or smaller than 4.225-0.008
or <4.233cm & >4.217