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xeze [42]
1 year ago
5

Sociologists want to test whether the number of homeless people in a particular urban area is increasing. In 2010, the average n

umber of homeless people per day who sought shelter was 42.3 (σ = 6.2). Data from the current year reveal that the mean number of people seeking shelter per day is 45.3. Compute the test statistic using an alpha = .01 and n = 1000.
Mathematics
1 answer:
Kobotan [32]1 year ago
7 0

Answer:

The test statistic value is 15.3.

Step-by-step explanation:

The hypothesis for this test is:

<em>H</em>₀: The average number of homeless people is not increasing, i.e. <em>μ</em> = 42.3.

<em>H</em>ₐ: The average number of homeless people is increasing, i.e. <em>μ</em> > 42.3.

Given:

\bar x=45.3\\\sigma=6.2\\n=1000

As the population standard deviation is provided use a single mean <em>z</em>-test for the hypothesis testing.

The test statistic is:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{45.3-42.3}{6.2/\sqrt{1000}}=15.3

Thus, the test statistic value is 15.3.

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The population of Smalltown in the year 1890 was 6,250. Since then, it has increased at a rate of 3.75% each year. • What was th
Vikki [24]

Answer:

  • year 1915 :   15,689
  • year 1940 :  39,381

t = 137.9 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t  

Where:

p = original population

r = growing rate (decimal form)

t= years

A = population after t years

Replacing with the values given:

A = 6,250 (1 + 3.75/100)^t

A = 6,250 (1 + 0.0375)^t

A = 6,250 (1.0375)^t

  • So, by the year 1915 :

1915-1890 = 25 years passed (t)

A = 6,250 (1.0375)^25

A = 15,689

  • by the year 1940 :

1940-1890 = 50 years passed (t)

A = 6,250 (1.0375)^50

A = 39,381

  • When will the population reach 1,000,000?. We have to subtitute A=1000000 and solve for t.

1,000,000= 6,250 (1.0375)^t

1,000,000/ 6,250 =(1.0375)^t

160 = 1.0375^t

log 160 = log 1.0375^t

log 160 = (t ) log 1.0375

log160 / log 1.0375= t

t = 137.9 years

8 0
1 year ago
The parabola y=x^2y=x 2 y, equals, x, start superscript, 2, end superscript is reflected across the xxx-axis and then scaled ver
kramer

ANSWER

The equation of the new parabola is

y =  - 5 {x}^{2}

EXPLANATION

The given parabola has equation:

y =  {x}^{2}

If this parabola is reflected in the x-axis, its equation becomes :

y =  -  {x}^{2}

When this parabola is scaled vertically by a factor of 5, the equation becomes,

y =  - 5 {x}^{2}

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Samantha wants to use her savings of $1150 to buy shirts and watches for her family. The total price of the shirts she bought wa
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The cost of the shirts is stable, so we can subtract $1150 - $84, which = $1066. Now we want to find how many watches we can buy with $1066, or how many times $99 fits into $1066. So divide 1066 by 99 to get 10.77. You can't buy 77ths of a watch, so round it down to 10 and you have your answer. Samantha can buy 10 watches.
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Here is how to do that conversion...

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The random variable Y is normally distributed with a mean of 470, and the value Y=340 is at the 15th percentile of the distribut
adell [148]
The empirical rule says that about 68% of any normal distribution lies within one standard deviation of the mean. This leaves 32% of the distribution that lies outside this range, with about 16% to either side.

At the 16th percentile, there is a value of Y=y such that

\mathbb P(Y

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You're told that Y=340 lies at the 15th percentile, so that

\mathbb P(Y

Roughly, then, it'd be fair to say that y\approx340. So you have

\dfrac{340-470}\sigma\approx-1\implies\sigma\approx130

which falls between (A) and (B). To narrow down the choice, notice that y would have be slightly larger than 340 in order to have \mathbb P(Y. This brings y closer to the mean, and thus suggests the standard deviation for the distribution is actually smaller than our approximation.

This tells us that (A) is the answer.
4 0
1 year ago
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