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xeze [42]
2 years ago
5

Sociologists want to test whether the number of homeless people in a particular urban area is increasing. In 2010, the average n

umber of homeless people per day who sought shelter was 42.3 (σ = 6.2). Data from the current year reveal that the mean number of people seeking shelter per day is 45.3. Compute the test statistic using an alpha = .01 and n = 1000.
Mathematics
1 answer:
Kobotan [32]2 years ago
7 0

Answer:

The test statistic value is 15.3.

Step-by-step explanation:

The hypothesis for this test is:

<em>H</em>₀: The average number of homeless people is not increasing, i.e. <em>μ</em> = 42.3.

<em>H</em>ₐ: The average number of homeless people is increasing, i.e. <em>μ</em> > 42.3.

Given:

\bar x=45.3\\\sigma=6.2\\n=1000

As the population standard deviation is provided use a single mean <em>z</em>-test for the hypothesis testing.

The test statistic is:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{45.3-42.3}{6.2/\sqrt{1000}}=15.3

Thus, the test statistic value is 15.3.

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Given data :
a₃ = 9/16
aₓ = -3/4 · aₓ₋₁
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To find the 7th term (a₇):

We know that aₓ = -3/4 · aₓ₋₁
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a₃ = -3/4 · a₃₋₁
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Again,
aₓ = -3/4 · aₓ₋₁
a₄ = -3/4 · a₄₋₁
a₄ = -3/4 · a₃
a₄ = -3/4 · 9/16
a₄ = -27/64
a₄ = -27/64

For a₅,
aₓ = -3/4 · aₓ₋₁
a₅ = -3/4 · a₅₋₁
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a₅ = -3/4 × -27/64
a₅ = 81/256

For a₆,
aₓ = -3/4 · aₓ₋₁
a₆ = -3/4 · a₆₋₁
a₆ = -3/4 · a₅
a₆ = -3/4 × 81/256
a₆ = -243/1024

For a₇,
aₓ = -3/4 · aₓ₋₁
a₇ = -3/4 · a₇₋₁
a₇ = -3/4 · a₆
a₇ = -3/4 × -243/1024
a₇ = 729/4096
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