Answer:
The correct answer is 0.15
Step-by-step explanation:
According to the given scenario, the probability is as follows:
X
Bin (n,p)
Here
n = 8
p = 0.20 or 20%
Now this is a binomial probability distribution
= 0.15
Hence, the correct answer is 0.15
Answer:
Option B. 5P5 × 20P15
Step-by-step explanation:
It is very important to remember that the second grade students are sitting in the front row, therefore, it is only necessary to organize 15 first grade students in 20 seats.
Permutations allow you to calculate the number of ways in which m objects can be arranged in n positions.
The permutation of m in n is written as:
nPm
Where n is the number of elements and m are chosen.
The way in which the 5 second grade students can be organized in the 5 seats is from the first row is:
5P5
Then, the number of ways in which 15 first-year students can be organized into 20 seats is:
20P15
Then, the number of ways to organize all students on the bus is the product of both permutations
5P5 * 20P15
Answer:
h(x) = |x+10|---------------------------------------------------------
Explanation:
To shift the graph 10 units to the left, we replace x with x+10. What's really going on is that the xy axis shifts 10 units to the right (because x is now x+10; eg, x = 2 ---> x+10 = 2+10 = 12) so it appears that the graph is moving to the left. The general rule is h(x) = g(x+10).
So,
g(x) = |x|
g(x+10) = |x+10| ... every x has been replaced with x+10
h(x) = g(x+10)
h(x) = |x+10|
We can use a graphing tool like GeoGebra to visually confirm we have the right answer (see attached). Note how a point like (0,0) on the green graph moves to (-10,0) on the red graph.
D/2=r
vcone=(1/3)hpir^2
given
d=30
h=9.1
d/2=30/2=15=r
v=(1/3)9.1pi15^2
v=(9.1/3)pi225
v=682.5pi
use 3.141592 to aprox pi
v=2144.13654
the closese is the first one
answer would be 2120 m³
