Answer:
tan−1(StartFraction 6.9 Over 9.8 EndFraction)
Step-by-step explanation:
tan−1(StartFraction 6.9 Over 9.8 EndFraction)
tan = opp/adj = 9.8/6.9
tan -1 = 1 / tan = 1 / (9.8 /6.9) = 6.9 /9.8
X + x + 10 + 2x - 16
x = mia's score
x + 10 = erick's score
2x - 16 = isabelle's score
the entire expression is the sum of all 3 scores <==
We have to find the" ratio of the area of sector ABC to the area of sector DBE".
Now,
the general formula for the area of sector is
Area of sector= 1/2 r²θ
where r is the radius and θ is the central angle in radian.
180°= π rad
1° = π/180 rad
For sector ABC, area= 1/2 (2r)²(β°)
= 1/2 *4r²*(π/180 β)
= 2r²(π/180 β)
For sector DBE, area= 1/2 (r)²(3β°)
= 1/2 *r²*3(π/180 β)
= 3/2 r²(π/180 β)
Now ratio,
Area of sector ABC/Area of sector DBE =
= 4/3
Place value is the value each digit has in its position: in order from higher to lower value, there is thousands, hundreds, tens, and ones.
When you divide by 10, you are moving (only once) every digit from its present place value to the right.
For example 6430 : 10= 643, you have moved every digit to the right, making the zero disappear (or better yet, separated by a hidden and in this case useless comma).
Answer: 10/117
Step-by-step explanation:
3 distinct letters and 4 distinct nonzero digits
For letters: A → Z = 26 options
For numbers: 1 → 9 = 9 options
As we have 26 options for letters and 9 for numbers and they have to be distinct, for the total of codes we have
Total of codes: 26.25.24.9.8.7.6
For the particular code asked, we have 5 options of vowels and 4 options of even numbers, so
5.25.24.8.7.6.4
probability: <u>5.25.24.8.7.6.4</u> = <u>10</u>
26.25.24.9.8.7.6 117
