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lapo4ka [179]
1 year ago
10

Jay stores hay in cubic stacks on his farm. If the length of each stack is 2/3 yards, what is the volume of hay in each stack? 1

/3 cubic yards, 4/9 cubic yards, 1/9 cubic yards, 8/27 cubic yards
Mathematics
2 answers:
siniylev [52]1 year ago
5 0

Answer: The volume of hay in each stack is 8/27 yards

Step-by-step explanation:

Since, the volume of a cube = (side)³

Here, the side of the a cubic stack = \frac{2}{3} yards,

Hence, the volume of a cubic stack,

V=(\frac{2}{3})^3

=\frac{8}{27} cube yard.

⇒ The volume of hay in each stack is 8/27 yards

Natasha2012 [34]1 year ago
3 0
\left( \dfrac{2}{3}\,yd\right)^{3}=\dfrac{8}{27}\,yd^{3}

The 4th selection is appropriate.
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In two or more complete sentences explain how you would set up and solve the following equation: Peter opened his account with $
Black_prince [1.1K]
Peter will have $910 - $40 * x on his account, where x is the number of the weeks. Marla will have $470 - $20 * x.
910 - 40 x = 470 - 20 x
910 - 470 = 40 x - 20 x
440 = 20 x
x = 440 : 20
x = 22
910 - 40 * 22 = 910 - 880 = $30
470 - 20 * 22 = 470 - 440 = $30
Answer: Their accounts will be equal in 22 weeks ( both of them will have $30 ).
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2 years ago
Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

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2 years ago
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frutty [35]
When you divide, the exponents subtract. -9 - (-12) = 3
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The sum of two numbers is 43. One number is five less than three times the other number. What is the largest number?
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Answer:

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Step-by-step explanation:

Let the numbers be x and y.

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x + y = 43

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y = 3x - 5

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x + y = 43

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Since the second equation is already solved for y, we will use the substitution method. We substitute 3x - 5 for y in the first equation.

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The first number is 12. Now we find the second number.

x + y = 43

12 + y = 43

y = 31

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