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Sloan [31]
2 years ago
14

Explain how your work your knowledge of place value helps you divide a number in thousands by whole numbers to 10 give a example

to support your explanation.ill give you soo much points like 30 some thing no 100
Mathematics
1 answer:
Anna71 [15]2 years ago
3 0
Place value is the value each digit has in its position: in order from higher to lower value, there is thousands, hundreds, tens, and ones.
When you divide by 10, you are moving (only once) every digit from its present place value to the right.
For example 6430 : 10= 643, you have moved every digit to the right, making the zero disappear (or better yet, separated by a hidden and in this case useless comma).
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Evaluate 3/2y-3+ 5/3z when y= 6 and z=3
wolverine [178]
1 plus 3 equals 4
Your answer is 4

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Adam is using the equation (x)(x + 2) = 255 to find two consecutive odd integers with a product of 255. When Adam solves the pro
kondaur [170]
\bf (x)(x+2)=255\implies x^2+2x=255\implies x^2+2x-255=y
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\textit{setting y=0}\implies x^2+2x-255=0
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\textit{now, factoring that}
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(x+17)(x-15)=0\implies 
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notice the picture of the graph added here
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2 years ago
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Сумму чисел 165 и 633 уменьшили в несколько раз получили 266. Чему равно неизвестное число?
Whitepunk [10]

Answer:

3

Step-by-step explanation:

The sum of 165 and 633 will be

165+633=798

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The sum is reduced three times.

Therefore, as per the question, this sum was reduced three different times

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The final velocity of an object moving in on one dimension is given by the formula v = u + at, where u is the initial velocity,
agasfer [191]

Answer:

Given Below

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8 0
2 years ago
"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
Westkost [7]

Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b) Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c) P(\bar X >31.25)=0.006=0.6\%

d) P(\bar X >28.25)=0.9997=99.97\%

e) P(28.25

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

3 0
2 years ago
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