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Gnesinka [82]
1 year ago
14

Simplify fully12xy24xy​

Mathematics
1 answer:
Darina [25.2K]1 year ago
5 0

Answer:

288xy

Step-by-step explanation:

First, you multiply 12 by 24 and you get 288. Next, you can't forget the variables, so you add those to the end and get, 288xy.

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Darcie wants to crochet a minimum of 3 blankets blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a
bearhunter [10]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal is:

s\leq 15

Thus, Darcie can skip a maximum of 15 days.

Step-by-step explanation:

Question

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Given:

Darcie has a target to crochet a minimum of 3 blankets.

Rate at which Darcie crochets = \frac{1}{15} of a blanket per day.

Darcie has 60 days to crochet the blankets

To write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

The number of days Darcie can skip crocheting is represented by s

So, number of days left for Darcie to crochet = 60-s

In 1 day Darcie crochets  \frac{1}{15} of a blanket.

So, in (60-s) days she will crochet = \frac{1}{15}(60-s)  blankets.

Her aim is to crochet at least 3 blankets.

Thus, the inequality can be given as:

\frac{1}{15}(60-s)\geq 3

Solving for s

Multiplying both sides by 15 to remove fractions.

15\times\frac{1}{15}(60-s)\geq 3\times 15

60-s\geq 45

Subtracting both sides by 60.

60-60-s\geq 45-60

-s\geq -15

Dividing both sides by -1.

\frac{-s}{-1}\leq \frac{-15}{-1}     [ On dividing by negative number the sign of the inequality is reversed]

∴ s\leq 15

Thus, Darcie can skip a maximum of 15 days.

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