paula charges $12 to shovel a driveway she shoveled 6 driveaways on saturday and then some more on sunday she made $144 for the
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
The area of the shaded region is
Step-by-step explanation:
<u><em>The correct question is</em></u>
A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?
The shaded region is the area outside the smaller circle and inside the larger circle
we know that
To find out the shaded region subtract the area of the smaller circle from the area of the larger circle
so
simplify
where
r_a is the radius of the larger circle
r_b is the radius of the smaller circle
we have
substitute
assume
substitute