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Anvisha [2.4K]
1 year ago
12

Veronica put a $400 necklace on layaway by making a 10% down payment

Mathematics
1 answer:
JulsSmile [24]1 year ago
7 0

7 weeks APEX LEARNING

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PLEEEEEEEEEEASE HELP ASAP
Paraphin [41]

The answer is D. $431.04.

A semi-circle, is half a circle. You need to get the area of the semi-circle to get the price for the whole thing. Since the door is 34 inches, we can assume that the diameter of the window would be 34 inches.

Okay, since the area of the circle is: πr², we just need to divide the equation by 2. So you will have the equation:

A =\dfrac{\pi(r^{2})}{2}

Where:

π=3.14

r = radius

All we have is the diameter, and what we need is the radius. The radius is half of the diameter, so we divide the measurement of the diameter by two.

r=\dfrac{d}{2}\\\\ r=\dfrac{34in}{2}\\\\ r=17in

So now that we have the radius, let's put that into our area equation:

A=\dfrac{\pi(r^{2})}{2}\\ \\ A=\dfrac{(3.14)(17in^{2})}{2}\\ \\ 453.73in^{2}

The area of the semi-circle window is 453.73in².

Now let's get how much that would cost by multiplying the area by the price per square inch.

(453.73in^{2})(\dfrac{\$0.95}{in^{2}}) = \$431.04

The semi-circle would cost $431.04.

5 0
2 years ago
kadeem and quinn both drive 25 miles. Kadeem drives at a constant speed of 50 miles an hour. Quinn drives at a constant speed of
VARVARA [1.3K]

Answer:

Kadeem takes 10 minutes longer  to drive 25 miles.

Step-by-step explanation:

50m/hr = 25m/ half an hour

75m/hr = 25m/20 minutes

3 0
2 years ago
robin is making bead necklaces she want to use 717 beads to make 57 necklaces. if she wants each necklaces to have the same numb
EleoNora [17]

717=12\cdot684+33

<u>33 beads</u>

7 0
2 years ago
On this graph, 4:00 p.m. occurs at 16 hours after midnight, and 6:00 p.m. occurs at 18 hours after midnight. Which statements ar
KatRina [158]

Answer:

TRUE OPTIONS ARE:

<em>"The temperature increased until 4:00 p.m. "</em>

<em>"The temperature decreased after 6:00 p.m. "</em>

<em>"The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m."</em>

Step-by-step explanation:

<em>graph attached and complete question below:</em>

<em>Which statements are true about the temperatures Luis  recorded on the graph? Check all that apply. </em>

  • <em>The temperature increased until 4:00 p.m. </em>
  • <em>The temperature was not recorded between 4:00 p.m.  and 6:00 p.m. </em>
  • <em>The temperature decreased after 6:00 p.m. </em>
  • <em>The temperature increased and then decreased before  holding constant. </em>
  • <em>The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m.</em>

<em />

Until 1600 hours, the graph increases, so we can say temperature increased until 4.00 pm (FIRST OPTION TRUE).

From 1600 to 1800 hours (4 - 6pm), the temperature stayed same (horizontal line). This doesn't mean the temperature wasn't recorded. (2nd OPTION FALSE).

After 1800 hours (6pm), the line goes downward, so temperature decreased after 6 pm. (3rd OPTION TRUE).

If you look at the temperature graph, we can see temperature increased, then increased more, then constant, then decreased. Thus the 4th option isnt true. (4th OPTION FALSE).

Before 12, the increase isn't as sharp as after 12. After 12 temperature increase has more slope, so this increase is more. (5th OPTION TRUE).

7 0
1 year ago
Read 2 more answers
Let C be the closed, piecewise smooth curve formed by traveling in straight lines between the points (-2,1), (-2,-3), (1,-1) , (
Greeley [361]

The given points are the vertices of the quadrilateral

Q=\left\{(x,y)\mid-2\le x\le1,\dfrac{2x-5}3\le y\le\dfrac{4x+11}3\right\}

By Green's theorem, the line integral is

\displaystyle\int_C2xy\,\mathrm dx+xy^2\,\mathrm dy=\iint_Q\frac{\partial(xy^2)}{\partial x}-\frac{\partial(2xy)}{\partial y}\,\mathrm dA

=\displaystyle\int_{-2}^1\int_{(2x-5)/3}^{(4x+11)/3}y^2-2x\,\mathrm dy\,\mathrm dx=\boxed{61}

6 0
2 years ago
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