On this graph, 4:00 p.m. occurs at 16 hours after midnight, and 6:00 p.m. occurs at 18 hours after midnight. Which statements ar
e true about the temperatures Luis recorded on the graph? Select THREE answers.
2 answers:
Answer:
TRUE OPTIONS ARE:
<em>"The temperature increased until 4:00 p.m. "</em>
<em>"The temperature decreased after 6:00 p.m. "</em>
<em>"The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m."</em>
Step-by-step explanation:
<em>graph attached and complete question below:</em>
<em>Which statements are true about the temperatures Luis recorded on the graph? Check all that apply. </em>
- <em>The temperature increased until 4:00 p.m. </em>
- <em>The temperature was not recorded between 4:00 p.m. and 6:00 p.m. </em>
- <em>The temperature decreased after 6:00 p.m. </em>
- <em>The temperature increased and then decreased before holding constant. </em>
- <em>The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m.</em>
<em />
Until 1600 hours, the graph increases, so we can say temperature increased until 4.00 pm (FIRST OPTION TRUE).
From 1600 to 1800 hours (4 - 6pm), the temperature stayed same (horizontal line). This doesn't mean the temperature wasn't recorded. (2nd OPTION FALSE).
After 1800 hours (6pm), the line goes downward, so temperature decreased after 6 pm. (3rd OPTION TRUE).
If you look at the temperature graph, we can see temperature increased, then increased more, then constant, then decreased. Thus the 4th option isnt true. (4th OPTION FALSE).
Before 12, the increase isn't as sharp as after 12. After 12 temperature increase has more slope, so this increase is more. (5th OPTION TRUE).
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Answer:
A 90% confidence interval of the true mean is [$119.86, $123.34].
Step-by-step explanation:
We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.
Also, the standard deviation of the population was $6.36.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = ~ N(0,1)
where, = sample mean amount of money spent on textbooks = $121.60
= population standard deviation = $6.36
n = sample of students = 36
= population mean
<em>Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.</em>
<em />
So, 95% confidence interval for the population mean, is ;
P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level
of significance are -1.645 & 1.645}
P(-1.645 < < 1.645) = 0.90
P( <
<
) = 0.90
P( <
<
) = 0.90
<u>90% confidence interval for</u> = [
,
]
= [ ,
]
= [$119.86, $123.34]
Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].
Answer:
second transformation is a reflection across the line containing AB
Step-by-step explanation:
The options are : a reflection across the line containing AB , a rotation about point B, a reflection across the line containing CB, a rotation about point C
The diagram is attached below
The triangle ABC is transformed to get triangle QRS
First transformation is the translation of vertex B to vertex R.
To get the same triangle QRS, the triangle to be reflected across the line AB
So second transformation is a reflection across the line containing AB
