Answer:
c. A two-tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.
Step-by-step explanation:
Let p1 be the average score on a final exam who texted on a regular basis during the lectures for a particular class
And p2 be the average score on a final exam who did not texted at all during the lectures for a particular class
According to the Cameron's point of interest, null and alternative hypotheses are:
p1 = p2
p1 ≠ p2
Two tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.
<span>( 7 x - 11 )
<span>( 7 - 5x )</span></span>
The answer is C.................................................
It is
12000 x (1.06)^12 + 50000 x (1.06)^6
= 95,072.31
start of 4th year to end of 6th year = 6 semi-annual periods where interest is compounded for the second deposit