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2 years ago

9

Charles uses a graphing calculator to find a quadratic regression model f for a given set of data. When he compares model f to a

n earlier regression model g for the same data, he determines that g more accurately models the data. Which of the following statements are true? Select all that apply.
A. Function f likely had fewer residuals near the x-axis than function g.
B. Function f likely had more residuals equal to 0 than function g.
C. Function g had more residuals near the y-axis than function f.

1 answer:

makvit [3.9K]2 years ago

7 0

B I hope this helped I’m not sure

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The chance she will pull out a red paper is 20%.

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2 years ago

Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

<u>Given:</u>

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0

1 year ago

Read 2 more answers

5. You deposit $300 in an account Urat pays 1.48% annual interest. What is the balance after 1 year if the

kirill [66]

Answer:

The correct option is (A) $304.47.

Step-by-step explanation:

The formula to compute the future value (<em>FV</em>) of an amount (A), compounded daily at an interest rate of <em>r</em>%, for a period of <em>n</em> years is:

$FV=A\times [1+\frac{r\%}{365}]^{n\times 365}$

The information provided is:

A = $300

r% = 1.48%

n = 1 year

Compute the future value as follows:

$FV=A\times [1+\frac{r\%}{365}]^{n\times 365}$

$=300\times [1+\frac{0.0148}{365}]^{365}\\\\=300\times (1.00004055)^{365}\\\\=300\times 1.014911\\\\=304.4733\\\\\approx \$304.47$

Thus, the balance after 1 year is $304.47.

The correct option is (A).

8 0

1 year ago