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vampirchik [111]
1 year ago
5

The newspaper in Haventown had a circulation of 80,000 papers in the year 2000. In 2010, the circulation was 50,000. With x = 0

representing the year 2000, the graph below models this scenario.
What number will complete the point-slope equation that models this scenario?

y 50,000 = (x 10)
Mathematics
2 answers:
mixas84 [53]1 year ago
7 0
-3000 is correct
Hope this helps :D
Alik [6]1 year ago
4 0

Answer:

-3000

Explanation:

The missing number is the slope of the line.

To calculate the slope, we use the formula

m=\frac{y_2-y_1}{x_2-x_1}

Using the points (0, 80000) and (10, 50000) [<em>remember</em>, the year 2000 is at x = 0; this means the year 2010 would be at x=10] we have:

m = (50000-80000)/(10-0) = -30000/10 = -3000

The missing number, the slope, is -3000.

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Setler [38]
AFB = CFD = 31
BFC = 90 - (31+31) = 28
DFE = BFC = 28
CFE = CFD + DFE = 31 + 28 = 59
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1 year ago
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an artist is arranging tiles in rows to decorate a wall. each new row has 2 fewer tiles than the row below it. if the first row
valentinak56 [21]

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant

This problem is an Arithmetic Sequence

where

the first term is 23

and

the common difference is -2

In general we can write an Arithmetic Sequence as a rule

an=a1+d*(n-1)

where

a1 is the first term

d is the common difference

so

a1=23\\\\  d=-2

<u>Find the term a7</u>

an=a1+d*(n-1)\\ \\  a7=23+(-2)*[7-1]\\ \\\\ a7=23-12\\ \\\\    a7=11

therefore

<u>the answer is</u>

11\ tiles


7 0
1 year ago
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Gwendolyn francis is interested in buying a bond that pays $70 annually. the current price of the bond is $800. what is her curr
serg [7]
Below are the choices that can be found from other sources:

<span>A. 4%
B. 7%
C. 8%
D. 3.5%
E: 8.75%
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Below is the solution;

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</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
4 0
1 year ago
figure PQRS is a parallelogram. What are the measures of angles P and S? ∠P = 20°; ∠S = 160° ∠P = 40°; ∠S = 140° ∠P = 140°; ∠S =
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I believe it is C (p=140 s=40)
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Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not
tangare [24]

Answer:

a.

\bar p_1=0.05\\\bar p_2=0.067

b-Check illustration  below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let p_1  \& p_2 denote processes 1 & 2.

For p_1: T1=10,n1=200

For p_2:T2=20,n2=300

Therefore

\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067

b. To test for hypothesis:-

i.

H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

ii.For a two sample Proportion test

Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\

iii. for \frac{\alpha}{2}=(-1.96,+1.96) (0.5 alpha IS 0.025),

reject H_o if|Z|>1.96

iv. Do not reject H_o. The noncomforting proportions are not significantly different as calculated below:

z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}

z=-0.78

c.(1-\alpha).100\% for the p1-p2 is given as:

(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0
2 years ago
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