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vampirchik [111]
2 years ago
5

The newspaper in Haventown had a circulation of 80,000 papers in the year 2000. In 2010, the circulation was 50,000. With x = 0

representing the year 2000, the graph below models this scenario.
What number will complete the point-slope equation that models this scenario?

y 50,000 = (x 10)
Mathematics
2 answers:
mixas84 [53]2 years ago
7 0
-3000 is correct
Hope this helps :D
Alik [6]2 years ago
4 0

Answer:

-3000

Explanation:

The missing number is the slope of the line.

To calculate the slope, we use the formula

m=\frac{y_2-y_1}{x_2-x_1}

Using the points (0, 80000) and (10, 50000) [<em>remember</em>, the year 2000 is at x = 0; this means the year 2010 would be at x=10] we have:

m = (50000-80000)/(10-0) = -30000/10 = -3000

The missing number, the slope, is -3000.

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Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
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Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

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