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expeople1 [14]
1 year ago
6

You earned $62,715 this year and your Income tax calculator says you owe $8,818 in taxes. But you neglected to deduct $1,000 for

your dependent Grandfather and the $5,000 you put in an IRA. This reduces your income by $6,000 to $56,715. Your new effective tax rate is 10.70%. What is the difference in your old $62,715 based tax debt and the updated tax debt with another dependent and the IRA contribution?
Mathematics
1 answer:
zepelin [54]1 year ago
6 0

Answer: 2,749.50

Step-by-step explanation:

56,715*10.70% = 6068.505

8818 - 6068.505 = 2,749.50

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The average MCAT score follows a Normal distribution, with a mean of μ = 508 and a standard deviation of σ = 8. What is the prob
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Subtract the mean from the high score and divide by the standard deviation:

510 - 508 = 2

2/8 = 0.25

Using the Z tabe find the z value for 0.25 = 0.5987

Now subtract that value from 1:

1 - 0.5987 = 0.4013

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1 year ago
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The revenue each season from tickets at the theme part is represented by t(x) = 5x. The cost to pay the employees each season is
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Answer:  D. 15

Step-by-step explanation:

Given : The revenue each season from tickets at the theme part is represented by t(x) = 5x .

The cost to pay the employees each season is represented by r(x) = (1.5)x.

From the given graph , we can see that at 4th season, the profit = 15

Hence, the estimated profit after four seasons. =15

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1 year ago
In triangle RST, U is the midpoint of RS, V is the midpoint of ST, and W is the midpoint of TR. Use the triangle diagram to answ
Zolol [24]

(1)

we are given

U is the midpoint of RS

and we have

RU=12

so, we can use formula

RS=2RU

we can plug values

RS=2\times 12

RS=24............Answer

(2)

V is the midpoint of ST

so, we get

SV=VT

now, we can plug values

2x=11

divide both sides by 2

x=5.5.........Answer

(3)

now, we can find y

W is the midpoint of TR

so, we get

RW=WT

we can plug value

15.9=3y

divide both sides by 3

y=5.3

(4)

we can see that

triangles URW and RST are similar

so, their sides ratios must be equal

so, we get

\frac{RW}{RT} =\frac{UW}{ST}

we can plug values

\frac{15.9}{2\times 15.9} =\frac{UW}{2VT}

\frac{15.9}{2\times 15.9} =\frac{UW}{2\times 11}

UW=22\times \frac{15.9}{2\times 15.9}

UW=11...........Answer

(5)

we can see that

triangles SUV and RST are similar

so, their sides ratios must be equal

so, we get

\frac{SU}{SR} =\frac{UV}{RT}

now, we can plug values

\frac{12}{2\times 12} =\frac{UV}{2\times 15.9}

UV=2\times 15.9\times \frac{12}{2\times 12}

UV=15.9.............Answer

4 0
1 year ago
iven: C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the
ZanzabumX [31]

Answer:

See the attached figure for better explanation :

Step-by-step explanation :

1. By the unique line postulate, you can draw only one line segment : <u>BC</u>

Since only one line can be drawn between two distinct points.

2. Using the definition of <u>reflection</u>, reflect BC over l.

To find line segment which reflects BC over l, we will use the definition of reflection.

3. By the definition of reflection, C is the image of itself and <u>A</u> is the image of B.

Definition of reflection says the figure about a line is transformed to form the mirror image. Now, CD is perpendicular bisector of AB so A and B are equidistant from D forming the mirror image of each other.

4. Since reflections preserve <u>length</u>, AC = BC

In Reflection the figure is transformed to form a mirror image, Hence the length will be preserved in case of reflection.

8 0
1 year ago
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Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
1 year ago
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