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qaws [65]
2 years ago
6

The fuel efficiency for a 2007 passenger car was 31.2 mi/gal. For the same model of car, the fuel efficiency increased to 35.6 m

i/gal in 2012. The gas tank for this car holds 16 gallons of gas. Write and graph a linear function that models the distance that each car can travel for a given amount of gas (up to one tankful). Write the domain and range of each function using interval notation. Write and simplify a function f(g) that represents the difference in the distance that the 2012 car can travel and the distance that the 2007 car can travel on the same amount of gas. Interpret this function using the graphs of the functions from part a. Also, find and interpret f(16). Write the domain and range of the difference function using set notation.

Mathematics
1 answer:
Ierofanga [76]2 years ago
3 0

We have been given that fuel efficiency for a 2007 passenger car was 31.2 mi/gal and the same model of car, the fuel efficiency increased to 35.6 mi/gal in 2012. Also, the gas tank for this car holds 16 gallons of gas.

We need to write a function and graph a linear function that models the distance that each car can travel for a given amount of gas up to one tankful.

Let represent the functions as d_{1}(x) and d_{2}(x)  where d_{1} and d_{2} represent the distances traveled by car in years 2007 and 2012 and x represents the number of gallons. Therefore, we can express the required functions as:

d_{1}(x)=31.2x \text{ and } d_{2}(x) = 35.6x

Domain of both these functions are [0,16] and ranges are [0,499.2] and [0,569.6] respectively for years 2007 and 2012.

The difference function will be:

f(x)=35.6x-31.2x\\
f(x)=4.2x

f(16)=4.2*16=67.2

Domain of this function is [0,16] and range is [0,67.2].

The graphs are shown below.


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11 miles per hour

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The system of equations y = one-fourth x minus 1 and y = negative one-half x minus one-fourth is shown on the graph below. On a
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Step-by-step explanation:

<u>Step 1:  Convert into expressions</u>

y = one-fourth x minus 1 → y = \frac{1}{4}x-1

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1 year ago
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Find the surface area of the regular pyramid shown in the accompanying diagram. If necessary, express your answer in simplest ra
Oksana_A [137]

Answer:

The area of the pyramid is 360 unit²

Step-by-step explanation:

Given

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Required

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A = 10^2 + 2 * 10 * \sqrt{\frac{10^2}{4} + 12^2}

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A = 100 + 2 * 10 * \sqrt{\frac{100}{4} + 144}

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Take positive square root of 169

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The lifetime of a cheap light bulb is an exponential random variable with mean 36 hours. Suppose that 16 light bulbs are tested
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P(T

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Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

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P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{16})

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X \sim Exp(\mu=16)

Solution to the problem

For this case we are interested in the total T, and we can find the mean and deviation for this like this:

\bar X =\frac{\sum_{i=1}^n X_i}{n}=\frac{T}{n}

If we solve for T we got:

T= n\bar X

And the expected value is given by:

E(T) = n E(\bar X)= n \mu= 16*36=576

And we can find the variance like this:

Var(T) = Var(n\bar X)=n^2 Var(\bar X)= n^2 *\frac{\sigma^2}{n}=n \sigma^2

And then the deviation is given by:

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Answer:

The nearest hundred thousand of the provided number is 100,000.

Step-by-step explanation:

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The provided number can be written as 089,659

The digit at the hundred thousand place is 0.

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If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

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Here, the number at the ten thousands place is 8, so to round up the number increase the digit of hundred thousand place by 1.

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100,000

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1 year ago
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