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2 years ago

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A line passes through the points (9, 30) and (18, 30). Which statement is true about the line? It has a slope of zero because th

e change in the y-values is 0. It has no slope because the change in the y-values is 0. It has a slope of zero because the change in the x-values is 0. It has no slope because the change in the x-values is 0.

2 answers:

NISA [10]2 years ago

4 0

Answer:

It has a slope of zero because the change in the y-values is 0.

Step-by-step explanation:

ahrayia [7]2 years ago

3 0

Answer:

It has a slope of zero because the change in the y-values is 0.

Step-by-step explanation:

option a

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Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthes

lina2011 [118]

Answer:

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

In this problem we have

$(x_1,y_1)=(4,\frac{1}{3})$

$m=\frac{3}{4}$

substitute the given values

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

therefore

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

6 0

2 years ago

Read 2 more answers

If a = 0.6 repeating and b = 0.75, then a x b = blank and a/b = blank

atroni [7]

Answer:

a*b = 1/2

a/ b = 8/9

Step-by-step explanation:

a = 0.66666 and b = 0.75

To multiply it we write the decimal numbers in fraction form

a= 0.666666...

Multiply by 10 on both sides

10 a = 6.66666...

a = 0.66666...

Subtract the second equation

9a = 6

divide by 9 on both sides

$a=\frac{6}{9}=\frac{2}{3}$

so 0.6666 = 2/3

Now we convert 0.75 into fraction form

$0.75=\frac{0.75}{1}$

Multiply top and bottom by 100 to remove decimal

$\frac{75}{100} = \frac{3}{4}$

so 0.75 is 3/4

a= 2/3 and b = 3/4

$a*b = \frac{2}{3} * \frac{3}{4} = \frac{6}{12} = \frac{1}{2}$

$\frac{a}{b} = \frac{\frac{2}{3}}{\frac{3}{4}} = \frac{2}{3} * \frac{4}{3} =\frac{8}{9}$

8 0

2 years ago

Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model

Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

$\text{F}_(_n__1-1, n_2-1_)$

Here, $n_1$ = sample of 15 Claiborne models

$n_2$ = sample of 12 Klein models

So, the degrees of freedom = ( $n_1-1, n_2-1$ ) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.

If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.

(3) The test statistics that will be used here is F-test which is given by;

T.S. = $\frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }$ ~ $\text{F}_(_n__1-1, n_2-1_)$

where, $s_1^{2}$ = sample variance of the Claiborne models data = $\frac{\sum (X_i-\bar X)^{2} }{n_1-1}$ = 1.007

$s_2^{2}$ = sample variance of the Klein models data = $\frac{\sum (X_i-\bar X)^{2} }{n_2-1}$ = 2.653

So, the test statistics = $\frac{1.007}{2.653 } \times 1$ ~ $\text{F}_(_1_4,_1_1_)$

= 0.3796

Hence, the value of the test statistic is 0.3796.

3 0

2 years ago

arleen has a gift card for a local lawn and garden store. she uses the gift card to rent a roller for 4 days. it cost $17 per da

kaheart [24]

Answer:

We use negative values for the money Arleen spends.

a) We determine the change to the value on her gift card:

4(-35)+(-9)= -140+(-9)=-149

b) We determine the amount on money she has left on the gift card after renting the tiller and buying the rake:

200+(-149)=51

Since she has got $51 on her gift card and a wheelbarrow is $50 she is able to buy it:

51>50

RESULT

a) -$149 less b) yes

Step-by-step explanation:

7 0

2 years ago

The force of gravity between two objects is given by Fg = −Gm1m2/r2 , where G is the gravitational constant, m1 and m2 are the

Jet001 [13]

For two objects with a finite constant mass, Fg is inversely proportional to the square of the distance between them. As r gets smaller the gravitational force increases. When the two objects are touching Fg is highest. But the mass of an object is focussed at its centre, the centre of mass. When the objects are touching their centres of mass are still separated. The graph has a vertical asymptote at r=0, implying an infinite gravitational force.

4 0

2 years ago

Read 2 more answers