How many six-digit odd numbers are possible if the leftmost digit cannot be zero

For a school fundraiser, Mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the scho

Ket [755]

Answer: Total number of bracelet: 235

Step-by-step explanation:

Given:

Total budget= $1,500

Spend on wire = $250

Per braclet beads = $5.30

Find:

Total number of bracelet

Computation:

Total number of bracelet = [1,500 - 250]

Total number of bracelet = [1,250/ 5.30

Total number of bracelet = 235.849

Total number of bracelet = 235 [By round minium]

8 0

1 year ago

Simplify fully 13/2x - 5/x

puteri [66]

Hello There!

Find the LCD:

It is 2x

13/2x - 10/2x

The answer is 3/2x

Hope This Helps You!
Good Luck :)

- Hannah ❤

8 0

1 year ago

Read 2 more answers

A rectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.

Brilliant_brown [7]

The area of a rectangle is equal L x W

4 cm longer than it is wide L = 4 + W

L x W = 117 we replace L here

(4 + W ) x W = 117

4W + W ^2 = 117

4W + W ^2 -117 = 0
W ^2 +4 W -117 = 0

W² + 4W - 117 = 0


THEN u want to use the use the quadratic formula

OR Factoring gives us

(W + 13)(W - 9) = 0

W = -13 or 9

But it can't be negative, so

W = 9 and L= 9+4 = 13

3 0

2 years ago

Read 2 more answers

the daily profit in dollars of a specialty cake shop is described by the function P(x)=-3x^2+168x-1920. Where x is the number of

forsale [732]

Answer:

28

Step-by-step explanation:

We have the following function:

$f(x)=-3x^{2} +168x-1920$

where a=-3, b=168 and c=-1920

In order to calculate the maxium profit for the company, and how many cakes should be prepared in order to reach it, we have to calculate where the parabola's vertex is ubicated. To do so, we use the following formula:

$Xv= \frac{-b}{2a}$

$Xv= \frac{-168}{2.(-3)}$

$Xv= 28$

So 28 cakes should be prepared per day in order to maximize profit.

7 0

2 years ago

Read 2 more answers

A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr

erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

$p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034$

The estimated standard error is:

$\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316$

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

$LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096$

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0

1 year ago