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1 year ago

HELP PLEASE. Which regression equation best fits these data?

Mathematics

2 answers:

AlladinOne [14]1 year ago

7 0

Answer:

B. y = -0.58x^2 -0.43x +15.75

Step-by-step explanation:

The data has a shape roughly that of a parabola opening downward. So, you'll be looking for a 2nd-degree equation with a negative coefficient of x^2. There is only one of those, and its y-intercept (15.75) is in about the right place.

The second choice is appropriate.

_____

The other choices are ...

A. a parabola opening upward

C. an exponential function decaying toward zero on the right and tending toward infinity on the left

D. a line with negative slope (This might be a good linear regression model, but the 2nd-degree model is a better fit.)

creativ13 [48]1 year ago

5 0

Answer: y = -0.58x^2 -0.43x +15.75

Step-by-step explanation:

A P E X

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<h3><u><em>Solution:</em></u></h3>

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<u><em>Therefore, the given formula is:</em></u>

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$T=2\pi \sqrt{\frac{L}{32} }\\\\ \sqrt{\frac{L}{32} }=\frac{T}{2 \pi}\\\\\text{Taking square root on both sides }\\\\\frac{L}{32} = \frac{T^2}{4 \pi^2}\\\\L = \frac{T^2}{4 \pi^2} \times 32\\\\L = \frac{T^2}{\pi^2 } \times 8$

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