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REY [17]
1 year ago
7

Is 3/6 grater then 1/8

Mathematics
2 answers:
sashaice [31]1 year ago
4 0
True

3/6 = 0,5

1/8 = 0,125

0,5 > 0,125
dolphi86 [110]1 year ago
4 0

Answer: 1/6  1/8


Step-by-step explanation:


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It costs dylan $x$ dollars to buy $3$ tickets to the zoo. he discovers that if he were to buy $5$ tickets, he would receive a to
jonny [76]

So, if Dylan has x dollars and he bought 3 tickets with them, the tickets were priced at k dollars per ticket. If he bought 5 tickets with the x dollars and saved 12 total dollars, it would be the same as buying the tickets with x-12 dollars, so we have:

\frac{x}{3}=k\\ \frac{x-12}{5}=q

So, with this we have:

x=3k\\ x=5q+12

If we're looking for a number that satisfies these constraints, we can work with modular arithmetic. We have:

x\equiv 0 \pmod{3}\\ x\equiv 12 \pmod{5}

So, we can use the chinese remainder theorem here. So, we clearly have x=3k, which means:

3k\equiv12 \pmod{5} \implies\\ k \equiv 4 \pmod{5} \implies\\ k=5j+4

So, since we have x=3k, we also have x=3(5j+4)=15j+12.

So, clearly j=0 won't work so we should have j=1. That means our money per ticket for the five tickets is:

\frac{27-12}{5}=3

And our money per three tickets is:

\frac{27}{3}=9

This is easily verifiable. Three tickets needs 27 dollars and 5 tickets needs 15 dollars, which is 12 less than 27 dollars. So we have our money per three dollar ticket at 6 more than money per five dollar.

4 0
2 years ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

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2 years ago
If y = 8x − 2, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
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You just need to try with all of the pair f.ex
0,-2 -> put 0 in the x-> y=8*0-2=-2 so ok it is q possible pair of the function..
You try every pair till you find set where all the pairs fit
So set 1
1 and 6: 8*1-2=6 ok
2 and 14 : 8*2-2=14 ok
Hope I could help
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396$ because it’s right
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