Answer:
BC:BN=8:3
Step-by-step explanation:
ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.
Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD
But, BC= BN+NC
Therefore, BC:BN=(BN+NC):BN
⇒BC:BN=(3+5):3
⇒BC:BN=8:3
So the right options are:
Further explanation:
Given equation of line is:
2x+5y=10
We have to convert it into point-slope form
The co-efficient of x is the slope of the line
So,
As the required line is parallel to given line, it will also have same slope.
Let m1 be the slope of required line
Then the line will be:
Putting the value of slope
Putting (-5,1) in the equation to find the value of b
Putting the values of slope and b in equation
Multiplying the whole equation by 5 will give us:
5y = -2x-5
2x+5y = -5
Another form of equation of line is Point-slope form
Putting the values of slope and point in the equation, we get
So the right options are:
Keywords: Point-Slope form, Parallel lines
Learn more about point slope form at:
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