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2 years ago

12

riddle me this I'm thinking of a number it is odd is between 1 and 100 is higher than 20 it is smaller than the answer to 6 time

s 6 it is a multiple of 5 the sum of its digits is 7

2 answers:

Bogdan [553]2 years ago

6 0

I think it might be 27

Snezhnost [94]2 years ago

6 0

- odd number between 20 and 36
36 - 20 = 16 / 2 = 8 possible numbers
21, 23, 25, 27, 29, 31, 33, 35

- multiple of 5
leaves only two of the above possibilities
25 or 35

- sum of digits = 7
2 + 5 = 7

The number must be 25

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Ron is a basketball coach. The table shows the height in inches of the players Ron coaches

n200080 [17]

Range from 68 inches to 76 inches
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2 years ago

chen is buying a ham. He wants to divide it into 6.5-ounce servings for 12 people. write and solve a division equation to find w

OLga [1]

Answer:

Amount of people to serve x Serving Size = Size of ham

12 x 6.5 = ?

=78

Step-by-step explanation:

Looking for size ham chen should buy = ?

Amount of people to serve = 12

Serving Size = 6.5-ounce

Equation=

Amount of people to serve x Serving Size = Size of ham

12 x 6.5 = ?

=78

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2 years ago

Show that the Fibonacci numbers satisfy the recurrence relation fn = 5fn−4 + 3fn−5 for n = 5, 6, 7, . . . , together with the in

Sonja [21]

Answer with step-by-step explanation:

We are given that the recurrence relation

$f_n=5f_{n-4}+3f_{n-5}$

for n=5,6,7,..

Initial condition

$f_0=0,f_1=1,f_2=1,f_3=2,f_4=3$

We have to show that Fibonacci numbers satisfies the recurrence relation.

The recurrence relation of Fibonacci numbers

$f_n=f_{n-1}+f_{n-2}$ , $f_0=0,f_1=1$

Apply this

$f_n=(f_{n-2}+f_{n-3})+f_{n-2}=2f_{n-2}+f_{n-3}$

$f_n=2(f_{n-3}+f_{n-4})+f_{n-3}=3f_{n-3}+2f_{n-4}$

$f_n=3(f_{n-4}+f_{n-5})+2f_{n-4}=5f_{n-4}+3f_{n-5}$

Substitute n=2

$f_2=f_1+f_0=1+0=1$

$f_3=f_2+f_1=1+1=2$

$f_4=f_3+f_2=2+1=3$

Hence, the Fibonacci numbers satisfied the given recurrence relation .

Now, we have to show that $f_{5n}$ is divisible by 5 for n=1,2,3,..

Now replace n by 5n

$f_{5n}=5f_{5n-4}+3f_{5n-5}$

Apply induction

Substitute n=1

$f_5=5f_1+3f_0=5+0=5$

It is true for n=1

Suppose it is true for n=k

$f_{5k}=5f_{5k-4}+3f_{5k-5}$ is divisible 5

Let $f_{5k}=5q$

Now, we shall prove that for n=k+1 is true

$f_{5k+5}=5f_{5k+5-4}+3f_{5k+5-5}=5f_{5k+1}+3f_{5k}=5f_{5k+1}+3(5q)$

$f_{5k+5}=5(f_{5k+1}+3q)$

It is multiple of 5 .Therefore, it is divisible by 5.

It is true for n=k+1

Hence, the $f_{5n}$ is divisible by 5 for n=1,2,3,..

8 0

2 years ago

Triangle ABC has been reflected over the y- axis to create triangle A’B’C’. Which of the following statements is true ? B’C’ = 2

Klio2033 [76]

Answer:

B'C' = 2

Step-by-step explanation:

Just took the FLVS test and it was correct

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1 year ago

Ellen said she spent half her money for lunch and half of what was left for a movie. She now has $1.20. How much did she spend f

goldenfox [79]

Answer: She spend $1.20 for lunch.

Step-by-step explanation:

Let the total amount be 'x'.

Half of her money spend for lunch be $\dfrac{x}{2}$

Half of her money left for a movie be $\dfrac{x}{2}$

Amount she has now = $1.20

So, According to question, it becomes ,

$\dfrac{x}{2}=1.20\\\\x=1.20\times 2\\\\x=\$2.40$

Hence, Amount she spend for lunch is $\dfrac{x}{2}=\dfrac{2.40}{2}=\$1.20$

Therefore, she spend $1.20 for lunch.

8 0

1 year ago