Step-by-step explanation:
open the brackets by multiplying 4 and 28 =112
18+112= 130
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
That would be 1953.08
diameter = <span>circumference/pi, so reverse it and multiply 622 by 3.14</span>
Base pay = $11 x 40 or $440
$605 - 440 = $165 in overtime
Overtime is 1.5 (1 and a half times) her usual salary
11 x 1.5 = $16.50
$165 ÷ $16.50 = 10 hours of overtime.
600 ---> 250
600 - 250 = 350
350 / 5 = 70
Average decrease in value per year: $70
