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Oksi-84 [34.3K]
1 year ago
15

A farmer is having problems with birds eating her crops. She tries putting up different numbers of scarecrows to keep the birds

away. The average number of crops eaten is 200, and the average number of scarecrows she has put up is 20.
The farmer finds some of the linear regression equation:
number of crops eaten = a - 0.8*(number of scarecrows).
What is the value of the intercept?
Mathematics
1 answer:
Alexeev081 [22]1 year ago
3 0

Answer:

The value of the intercept is a=216.

Step-by-step explanation:

We define "s" as the number of scarecrows and "C" the number of crops eaten.

The farmer finds the linear regression equation:

C=a-0.8s

We have a linear function, for which we only know the slope (m=0.8) and a point within it (when s=20, C=200).

We can find a replacing the variables C asn s with the known point (20, 200):

C=a-0.8s\\\\C(20)=a-0.8(20)=200\\\\a=200+0.8*20=200+16\\\\a=216

The value of the intercept is a=216.

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Which of the following notations correctly describe the end behavior of the polynomial graphed below?
algol13

The right answer is C

Let me to explain. From the graph we know that the vertex of this parabola is V(0,8). This is a<em> maximum y-value.</em> We also know that the parabola <em>opens downward, </em>so the leading coefficient is negative. Given that the function is even and the leading coefficient is negative, it follows that the graph falls to the left and right. In a mathematical language this is:

x \rightarrow -\infty, f(x) \rightarrow -\infty \\ \\ x \rightarrow \infty, f(x) \rightarrow -\infty <em> </em>

4 0
1 year ago
An airplane is flying at a speed of 500 mi/h at an altitude of one mile. The plane passes directly above a radar station at time
d1i1m1o1n [39]

Answer:

a)s=\sqrt{1+d^2}

b)d(t)=500t

c)s(t) =\sqrt{1+250000t^2}

Step-by-step explanation:

d = Horizontal distance

s = the distance between the plane and the radar station

The horizontal distance (d), the one mile altitude, and s form a right triangle.

So, use Pythagoras theorem

Hypotenuse^2=Perpendicular^2+Base^2

s^2=1^2+d^2

a) s=\sqrt{1+d^2}

(b) Express d as a function of the time t (in hours) that the plane has flown.

distance = speed \times time

d(t)=500t

(c) Use composition to express s as a function of t.

s(t) =\sqrt{1+d^2}

using b

s(t) =\sqrt{1+(500t)^2}\\s(t) =\sqrt{1+250000t^2}

6 0
1 year ago
Given that a function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8, select the st
notka56 [123]

Options

  • (A)g(5) = 12
  • (B)g(1) = -2
  • (C)g(2) = 4
  • (D)g(3) = 18

Answer:

(D)g(3) = 18

Step-by-step explanation:

Given that the function, g, has a domain of -1 ≤ x ≤ 4 and a range of                       0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8

Then the following properties must hold

  1. The value(s) of x must be between -1 and 4
  2. The values of g(x) must be between 0 and 18.
  3. g(-1)=2
  4. g(2)=9

We consider the options and state why they are true or otherwise.

<u>Option A: g(5)=12</u>

The value of x=5. This contradicts property 1 stated above. Therefore, it is not true.

<u>Option B: g(1) = -2 </u>

The value of g(x)=-2. This contradicts property 2 stated above. Therefore, it is not true.

<u>Option C: g(2) = 4 </u>

The value of g(2)=4. However by property 4 stated above, g(2)=9. Therefore, it is not true.

<u>Option D: g(3) = 18</u>

This statement can be true as its domain is in between -1 and 4 and its range is in between 0 and 18.

Therefore, Option D could be true.

3 0
2 years ago
Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat
Ksenya-84 [330]

Answer:

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

5 0
1 year ago
You notice you are growing awfully fast lately. You have been growing at a rate of 3 inches per year. If you are 5 feet tall now
Cerrena [4.2K]

Answer:

4 years

Step-by-step explanation:

FYI this sounds like a personal problem

6 0
2 years ago
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