Answer:
Step-by-step explanation:
1 ) Given that

For a non homogeneous part
, we assume the particular solution is

2 ) Given that

For a non homogeneous part
, we assume the particular solution is

3 ) Given that
y′′ + 4y′ + 20y = −3sin(2x)
For a non homogeneous part −3sin(2x) , we assume the particular solution is

4 ) Given that
y′′ − 2y′ − 15y = 3xcos(2x)
For a non homogeneous part 3xcos(2x) , we assume the particular solution is

Answer:
4 years
Step-by-step explanation:
FYI this sounds like a personal problem
Answer:
The graph is shown below.
Step-by-step explanation:
Given:
The inequality of a line to graph is given as:

In order to graph it, we first make the 'inequality' sign to 'equal to' sign. This gives,

Now, we plot this line on a graph. The given line is of the form:
Where, 'm' is the slope and 'b' is the y-intercept.
So, for the line
, 
The y-intercept is at (0, -3).
In order to draw the line correctly we find another point. Let the 'y' value be 0.
Now, 
So, the point is (3, 0).
Now, we mark these points and draw a line passing through these two points.
Now, consider the line inequality
. The 'y' value is less than
. So, the solution region will be region below the line and excluding all the points on the line. So, we draw a broken line and shade the region below it.
The graph is shown below.
Answer:

Step-by-step explanation:
Given the differential model
![\dfrac{dP}{dt}=k[M-P(t)]](https://tex.z-dn.net/?f=%5Cdfrac%7BdP%7D%7Bdt%7D%3Dk%5BM-P%28t%29%5D)
We are required to solve the equation for P(t).

