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Oksi-84 [34.3K]
2 years ago
15

A farmer is having problems with birds eating her crops. She tries putting up different numbers of scarecrows to keep the birds

away. The average number of crops eaten is 200, and the average number of scarecrows she has put up is 20.
The farmer finds some of the linear regression equation:
number of crops eaten = a - 0.8*(number of scarecrows).
What is the value of the intercept?
Mathematics
1 answer:
Alexeev081 [22]2 years ago
3 0

Answer:

The value of the intercept is a=216.

Step-by-step explanation:

We define "s" as the number of scarecrows and "C" the number of crops eaten.

The farmer finds the linear regression equation:

C=a-0.8s

We have a linear function, for which we only know the slope (m=0.8) and a point within it (when s=20, C=200).

We can find a replacing the variables C asn s with the known point (20, 200):

C=a-0.8s\\\\C(20)=a-0.8(20)=200\\\\a=200+0.8*20=200+16\\\\a=216

The value of the intercept is a=216.

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A carpenter is building a rectangular bookcase with diagonal braces across the back, as shown. The carpenter knows that angle AD
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Refer to the diagram shown below.

Let x = m∠ADB.

Because m∠BDC is 32° greater than m∠ADB, therefore
m∠BDC = x + 32°

Each angle of a rectangle is 90°, therefore
x + (x+32) = 90
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2x = 58
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x+32 = 61°

Answer:
m∠BDC = 61°
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2 years ago
Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. He was
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Graph these two points: (0, 360), (30, 0)

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After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an
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Answer:

y=32000(1+0.08)^x

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Exponential growth function is y=a(1+r)^x

Where 'a' is the initial population

r is the rate of growth and x is the time period in years

a steady population of 32,000. So initial population is 32,000

an increase of 8% per year. the rate of increase is 8% that is 0.08

a= 32000 and r= 0.08

Plug in all the values in the general equation

y=a(1+r)^x

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4 0
2 years ago
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among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
2 years ago
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