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Tems11 [23]
2 years ago
8

A carpenter is building a rectangular bookcase with diagonal braces across the back, as shown. The carpenter knows that angle AD

C is a right angle and that m angle BDC is 32degrees greater than m angle ADB. Write and solve an equation to find m angle BDC and m angle ADB.

Mathematics
1 answer:
Valentin [98]2 years ago
8 0
Refer to the diagram shown below.

Let x = m∠ADB.

Because m∠BDC is 32° greater than m∠ADB, therefore
m∠BDC = x + 32°

Each angle of a rectangle is 90°, therefore
x + (x+32) = 90
2x + 32 = 90
2x = 58
x   = 29°
x+32 = 61°

Answer:
m∠BDC = 61°
m∠ADB = 29°

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Answer:

I believe the answer is A

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2 years ago
Which points are solutions to the linear inequality y < 0.5x + 2
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Answer:

Option 2,4 & 5

(1,-2)

(-1,-2)

(-3,-2)

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2 years ago
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Given: PQ ⊥ QR , PR=20, SR=11, QS=5 Find: The value of PS.
Neporo4naja [7]

1. PQR and is a right triangle, so you can calculate the measure of PQ by applying the Pythagorean Theorem. PR is the hypotenuse and QR and PQ are the legs:

PR^{2}=PQ^{2}+QR^{2}\\ PQ=\sqrt{PR^{2}-QR^{2}}\\ PQ=\sqrt{20^{2}-16^{2}} \\ PQ=12

2. PQS and is a right triangle too, so you can calculate the measure of PS by applying the Pythagorean Theorem as above. PS is the hypotenuse and PQ and QS are the legs:

PS=\sqrt{PQ^{2}+QS^{2}}=13

Therefore, the answer is: The value of PS is 13.

6 0
2 years ago
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Each August a restaurant rent is adjusted to the cost of living index. The rent has $1,550 a month, the cost-of-living index for
gulaghasi [49]
Answer:
new rent = $1607.35

Explanation:
Assume that the original rent is x

We are given that the rent increased by 3.7%.
This means that:
new rent = x + 3.7% x
new rent = x + 0.037 x

We are given that x = 1550, therefore:
new rent = 1550 + 0.037(1550)
new rent = 1550 + 57.35
new rent = $1607.35

Hope this helps :)
5 0
2 years ago
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A waterbed filled with water has the dimensions 8ft by 7 ft by .75 ft taking the density of water to be 1.00/gm cubed how many k
monitta

By definition, the density is given by:

D = \frac{m}{V}

Where,

m: mass

V: volume

Clearing the mass we have:

m = DV

The volume is given by:

V = (8) * (7) * (0.75)

V = 42ft ^ 3

Then, we have the following conversion:

1foot = 0.3048m

Applying the conversion we have:

V = 42 * (0.3048) ^ 3

V = 1.19m ^ 3

On the other hand we have the following conversions:

1m = 100cm

1Kg = 1000g

Applying the conversions for the density we have:

D = (1\frac{g}{cm^3})((\frac{100}{1})^3\frac{cm^3}{1m^3})(\frac{1}{1000}\frac{Kg}{g})=1000\frac{Kg}{m^3}

Then, the mass of the water is:

m = (1000) * (1.19)

m = 1190

Answer:

1190 kilgrams of water are required to fill the waterbed

7 0
2 years ago
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