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2 years ago

Given: PQ ⊥ QR , PR=20, SR=11, QS=5 Find: The value of PS.

Mathematics

2 answers:

Neporo4naja [7]2 years ago

6 0

1. PQR and is a right triangle, so you can calculate the measure of PQ by applying the Pythagorean Theorem. PR is the hypotenuse and QR and PQ are the legs:

$PR^{2}=PQ^{2}+QR^{2}\\ PQ=\sqrt{PR^{2}-QR^{2}}\\ PQ=\sqrt{20^{2}-16^{2}} \\ PQ=12$

2. PQS and is a right triangle too, so you can calculate the measure of PS by applying the Pythagorean Theorem as above. PS is the hypotenuse and PQ and QS are the legs:

$PS=\sqrt{PQ^{2}+QS^{2}}=13$

Therefore, the answer is: The value of PS is 13.

Ivahew [28]2 years ago

3 0

Answer:

13 is the correct answer!

Step-by-step explanation:

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A publishing company prints newspapers and magazines. Let NNN represent the number of newspapers and MMM represent the number of

adelina 88 [10]

Answer:

At most 800 magazines the company can print daily with the remaining number of ink cartridges.

Step-by-step explanation:

We are given the following in the question:

$0.5N+2.5M \leq 6000$

The above inequality gives the relation for daily supply of ink cartridges where N is the number of newspaper and M is the number of magazines.

Number of newspaper to be printed daily,N = 8000

We have to find the number of magazines at most can the company print daily with the remaining number of ink cartridges.

Puting the value in the given inequality,

$0.5(8000)+2.5M \leq 6000\\\Rightarrow 4000+2.5M \leq 6000\\\Rightarrow 2.5M \leq 2000\\\\\Rightarrow M \leq \dfrac{2000}{2.5}\\\\\Rightarrow M \leq 800$

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2 years ago

The number 4 is written on my whiteboard. Every time it rains, I multiply the number on the whiteboard by 2/3, erase the origina

marta [7]

The answer is 128/1875.

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2 years ago

21. Randy owns a computer store. In 1990, he sold 150 monitors. In 2000, he sold 900

lutik1710 [3]

Answer:

$y=75x+150$

Step-by-step explanation:

Let $y$ represent the number of monitors sold.

Given:

$x$ is the number of years since 1990.

So, for the year 1990, $x=0$ .

For the year 2000, 10 years passed. So, $x=10$ .

Now, monitors sold in 1990 are 150. So, at $x=0,y=150$

Monitors sold in 2000 are 900. So, at $x=10,y=900$

Thus, the two points are $(0,150)$ and $(10,900)$ .

The slope of a line with points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

Slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

For the points $(0,150)$ and $(10,900)$ , the slope is given as:

Slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\ m=\frac{900-150}{10-0}\\ m=75$

Now, the y-intercept is the point where $x=0$ . So, the point $(0,150)$ has $x$ value as 0.

So, the y-intercept is 150.

Equation of a line in slope-intercept form is given as:

$y=mx+b$

Where, $m$ is the slope and $b$ is the y intercept.

Here, $m=75$ and $b=150$ .

Therefore, the equation that represents the above data is given as:

$y=75x+150$

7 0

2 years ago

1+4=5, 2+5=12, 3+6=21,8+11=

klemol [59]

The answer is 40 because once you have 21 your just adding 19 and then that makes it 40.

8 0

2 years ago

An insurance company collected data from a class of high school sophomores on whether or not they have a cell phone and whether

NeX [460]

Answer:

C. Those who have a car tend to have a cell phone.

Step-by-step explanation:

The relative frequency for a data set n is calculated by dividing each frequency $x_i$ by n.

We have a table that relates the use of cars and cell phones.

First, we take from the table the population that has a car.

$n = 18$

Then, of the students who have a car, 12 have a cell phone and 6 do not have a cell phone.

Then we calculate the relative frequencies $f_{x_i}$ for those who have a cell phone and those who do not.

______________________________________________

Relative frequency Students with car n = 18.

-------------------------------------------------- --------------------------------------

Cell phone No cell phone Total n

12/18 6/18 18

_______________________________________________

Relative frequency Students with car n = 18.

-------------------------------------------------- --------------------------------------

Cell phone No cell phone Total n

0.666 0.333 18

________________________________________________

Most students who have a car also have a cell phone.

Now we calculate the relative frequency for students who do not have a car.

_______________________________________________

Relative frequency Students without a car n = 7

-------------------------------------------------- --------------------------------------

Cell phone No cell phone Total n

2/7 5/7 7

_______________________________________________

Relative frequency Students without a car n = 7

-------------------------------------------------- --------------------------------------

Cell phone No cell phone Total n

0.286 0.714 7

_______________________________________________

Most students who do not have a car do not have a cell phone either.

Then these data suggest that. Those who have a car tend to have a cell phone.

Option C

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2 years ago