Answer:
Pool 1 will be drained out just over a minute before pool 2.
Step-by-step explanation:
Pool 1
3700/31 = 119.35minutes
Pool 2
4228/42 = 100.67minutes
Pool 1 will be drained out just over a minute before pool 2
Answer:
There are 548.64 cm in 18 feet.
Step-by-step explanation:
We know that, 1 inch = 2.54 centimeters.
We need to convert 18 feet to centimeters
Also, 1 foot = 12 inch
Firstly we will convert 18 feet to inch.
18 feet = 12 × 18 inch
= 216 inch
Now to convert 18 feet to centimeters, multiply 216 inch by 2.54 cm as follows :
216 inch = 2.54×216 centimeters
= 548.64 cm
Hence, there are 548.64 cm in 18 feet.
Answer:
Hey!
The average of these amounts is : $183,636.70!
Step-by-step explanation:
To find the average, we have to add all the values up which gives...
= 918,183.50!
And then divide this number by the amount of values you added up...
*918,183.50 divided by 5 gives = $183,636.70*
So your average is $183,636.70!!
HOPE THIS HELPS!!
Answer:
Ruby’s function notation V(h) describes the volume of the pool after h number of hours. Hours is the independent variable and the total volume is the dependent variable.
Step-by-step explanation:
sample response
First, we have to find how many small cubes formed by the large cube.
To find the number of small cubes, we should calculate the volume of each large cube and small cube. Equalize the volume units to dm³
Dimension of large cube
s = 1 m
s = 10 dm
Volume of large cube
v = s³
v = 10³
v = 1,000 dm³
Dimension of small cube
s = 1 dm
Volume of small cube
v = s³
v = 1³
v = 1 dm³
Second, calculate the number of small cubes formed
n = volume of large cube / volume of small cube
n = 1,000 dm³ / 1 dm³
n = 1,000
There are 1,000 small cubes.
Third, calculate the height of the structure.
The structure is formed by 1,000 cubes. Each of them is 1 dm high.
The height of the structure is
h = 1 dm × 1,000
h = 1,000 dm
h = 100 m
The height of the structure is 1,000 dm or 100 m