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Airida [17]
2 years ago
6

Each August a restaurant rent is adjusted to the cost of living index. The rent has $1,550 a month, the cost-of-living index for

August was 3.7%. What is the new rent per month?
Mathematics
2 answers:
Anastaziya [24]2 years ago
7 0
The new rent per month is $1,607.35.
Given: Original rent = $1,550; Cost of Living Index = 3.7%
1. Multiply the original rent by the Cost of Living Index
1,550 * .037 = 57.35

2. Add the product of original rent and Cost of Living Index to the original rent
1,550 + 57.35 = $1,607.35
gulaghasi [49]2 years ago
5 0
Answer:
new rent = $1607.35

Explanation:
Assume that the original rent is x

We are given that the rent increased by 3.7%.
This means that:
new rent = x + 3.7% x
new rent = x + 0.037 x

We are given that x = 1550, therefore:
new rent = 1550 + 0.037(1550)
new rent = 1550 + 57.35
new rent = $1607.35

Hope this helps :)
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Gravity Hospital purchased a new item of equipment on January 1,20X1. The equipment has an estimated useful life of ten years an
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Answer:

  $25000

Step-by-step explanation:

If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.

  $10,000 = 0.40 × cost

  $10,000/0.40 = cost = $25,000

The acquisition cost of the equipment was $25,000.

8 0
2 years ago
Jose drove from newyork to Florida. Resting for 1 hour for every 5 hours he drove. if he drove for 35 hours. how many hours did
g100num [7]
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7 0
1 year ago
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A company receives shipments of a component used in the manufacture of a component for a high-end acoustic speaker system. When
Tanya [424]

Answer:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

Step-by-step explanation:

For this case we have a sample size of n = 250 units and in this sample they found that 24 units failed one or more of the tests.

We are interested in the proportion of units that fail to meet the company's specifications, and we can estimate this with:

\hat p = \frac{24}{250}= 0.096

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=2.33  

And the margin of error would be:

ME= 2.33*\sqrt{\frac{0.096*(1-0.096)}{250}}= 0.0434

4 0
2 years ago
1. When developing an interval estimate for the difference between two sample means, with sample sizes of n1 and n2, A. n1 must
Yuri [45]

Answer:

D. n1 and n2 can be of different sizes

Step-by-step explanation:

When we are trying to develop interval estimate for difference between two populations, we first select two samples from these populations. We get the interval using the required statistic.

These are:

- Sample size of both populations. Which are n1 and n2 respectively.

- then the Sample mean of two populations

- sample standard deviation.

The samples of different sample sizes can be used and we are not obligated to make use of the same sample size.

4 0
2 years ago
Frank left his house at 7 a.m. and drove to the airport at a speed of 50 mph. Lance left his house at 6 a.m. and drove to the sa
Tamiku [17]

Answer:

Lance will arrive at the airport at 10:00 AM.

Step-by-step explanation:

Lance left his house at 6:00 AM, and drove to the airport, which is 220 miles away, at 55mph; therefore, the time t it takes Lance to cover the distance of 220 miles is

t = \dfrac{220m}{55mph}

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Thus, it takes Lance 4 hours to reach the airport, and since he departed at 6:00 AM, he will arrive at the airport at (6+4):00 AM + 10:00 AM.

6 0
2 years ago
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