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Assoli18 [71]
2 years ago
10

Chaucer explores the idea that appearances can be deceiving through the character of the old woman. how does this theme relate t

o the earlier events in the tale?
Mathematics
1 answer:
Inessa [10]2 years ago
7 0
Since the plot of "The Wife of Bath's Tale" has at its heart a loathly lady who shape-shifts into a beautiful, young damsel, we might expect appearances to be important here. And they are, just not for the reason you might think. For instead of this being a tale about how a knight learns to appreciate people for what's on the inside and that outer appearances don't matter, it's a tale about how a knight learns to give up sovereignty to his wife. That sovereignty includes power over the body. The loathly lady's physical appearance becomes an important symbol of that body, so that, at the end of the tale, when she offers her husband a choice about how he wants her to look, she's in essence offering him control of her body. He grants this control back to her, thus proving his understanding of the doctrine of women's sovereignty in marriage. Medieval stories don't necessarily go in for the whole 'appearances don't mean anything' maxim anyway, as we've seen in the "General Prologue<span>."</span>
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A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
Mackenzie has a loyalty card good for a 20% discount at her local hardware store. What would her total in dollars and cents be,
8_murik_8 [283]

Answer: $14.0

Step-by-step explanation:

For us to calculate this question, we have to find 20% of $17.45 and then subtract the value gotten from $17.45. This will be:

= $17.45 - (20% × $17.45)

= $17.45 - (0.2 × $17.45)

= $17.45 - $3.49

= $13.96

= $14.0 to nearest cent

6 0
1 year ago
Read 2 more answers
Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the
xenn [34]

Answer:

As per the given statement:

The region bounded by the given curves about the y-axis, y = 13e^{-x^2}, y=0, x = 0 and x = 1

Using cylindrical shell method:

The volume of solid(V) is obtained by rotating about y-axis and the region under the curve y = f(x) from a to b is;

V = \int_{a}^{b} 2\pi x f(x) dx   where 0\leq a

where x is the radius of the cylinder

f(x) is the height of the cylinder.

From the given figure:

radius = x

height(h) =f(x) =y=13e^{-x^2}

a = 0 and b = 1

So, the volume V generated by rotating the given region:

V =2 \pi \int_{0}^{1} x ( 13e^{-x^2}) dx\\\\V=2\pi\left [ -\frac{13}{2}e^{-x^2} \right ]_{0}^{1}\\\\V=2\pi\left (-\frac{13}{2e}-\left(-\frac{13}{2}\right) \right )\\\\V=-\frac{13\pi }{e}+13\pi

therefore, the volume of V generated by rotating the given region is V=-\frac{13\pi }{e}+13\pi










5 0
1 year ago
A bottle of white wine at room temperature (68°f) is placed in a refrigerator at 4 p.m. its temperature after t hr is changing a
Nat2105 [25]
After an hour (4pm to 5pm) the temperature drops 18e⁻⁰˙⁶=9.9℉, so the temperature after an hour will be 68-9.9=58.1℉.
(The change -18e⁻⁰˙⁶ is negative indicating a drop in temperature.)
5 0
2 years ago
Read 2 more answers
your friend deposits $9500 in an investment account that earns 2.1% annual interest. what is the balance after 11 years when the
solmaris [256]

Answer:

The answer is "$ 11,961.43"

Step-by-step explanation:

Given values:

P =  $ 9500

r= 2.1 %

time (t)= 11 year

total quarterly year =4

Formula:

A= P (1+\frac{r}{n})^{nt}\\\\

quarterly time = 4 \times 11

                         = 44

A= P (1+\frac{r}{n})^{nt}\\\\

A = 9500 ( 1+ \frac{0.021}{4})^{44}\\\\A = 9500(\frac{4+ 0.021}{4} )^{44} \\\\A = 9500(\frac{4.021}{4} )^{44} \\\\A= 9500 (1.00525)^{44}\\\\A= 9500(1.25909819)\\\\A= 11,961. 43\\

8 0
1 year ago
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