<span>If Mary earns 7$ an hour, we need to multiplicate 7$ by the number of hours worked for the entire week so we can get the salary per week. And when we want to know how many hours she had worked, we have to "transform" the equation :
Salary per week = salary per hours x worked hours
Here, we know to informations : salary per hours and salary per week.
Worked hours = salary per week / salary per day
Worked hours = 143.50 / 7
Worked hours = 20.5
The greatest number of hours thats he works is 20h30.</span>
Answer:
Step-by-step explanation:
Correct steps to find the value of 'a' should be,
Braulio's synthetic division should be,
-1 | 1 5 a -3 11
<u> -1 -4 (4 - a) (a - 1) </u>
1 4 (a - 4) (1 - a) (a + 10)
Here remainder is (a + 10).
So (a + 10) = 17 ⇒ a = 7
Braulio Incorrectly found a value of 'a' because he should have used (-1) instead of 1.
Zahra's calculation by remainder theorem should be,
p(x) = x⁴ + 5x³ + ax² - 3x + 11
p(-1) = (-1)⁴ + 5(-1)³ + a(-1)² - 3(-1) + 11
= 1 - 5 + a + 3 + 11
= (a + 10)
Since, remainder of the solution is 17,
(a + 10) = 17 ⇒ a = 7
Zahra incorrectly found the value of 'a' because she incorrectly solved the powers to (-1).
Assuming the velocity is as written,
a = 3(2) = 6
If you meant 3(2t+1)⁰.⁴, then
a = 2.4/(2t+1)⁰.⁶
as usual,
s = 25 + 1/2 at²
= 25 + 3t²
or
= 25 + 1.2(2t+1)¹.⁴
To solve this question, you need to find how long jump is. For 2m high with <span>1.67 m/s2 it would be:
h= 1/2 gt^2
2= 1/2 * (1.67) t^2
t^2= 1.67
t= 1.29
If the speed is 20 mph and the jump is 2 second, the distance traveled would be:
20 miles/ hour * 1.29 second * (1 hour/3600second)= 0.007179 miles
If you need to convert it to meter then: </span>0.007179 mile * 1609.34meter/ mile= 11.55 meter
Two figures are similar if one is the scaled version of the other.
This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.
To be more precise, you only need two steps to prove that every two circles are similar:
- Translate one of the two circles so that they have the same center
- Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well
Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.
Recapping, we have:
- Start with circle X and radius r
- Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
- Scale the radius of circle X' until it becomes
. This new circle, say X'', is similar to X' because you only scaled it
So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.
