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hammer [34]
2 years ago
5

The measure of central angle XYZ is StartFraction 3 pi Over 4 EndFraction radians. What is the area of the shaded sector? 32Pi u

nits squared 85 96Pi units squared 256Pi units squared
Mathematics
2 answers:
Tems11 [23]2 years ago
5 0

Answer:

<em>96π units²</em>

Step-by-step explanation:

Find the diagram attached

Area of a sector is expressed as;

Area of a sector = θ/2π * πr²

Given

θ = 3π/4

r = 16

Substitute into the formula

area of the sector = (3π/4)/2π * π(16)²

area of the sector = 3π/8π * 256π

area of the sector = 3/8 * 256π

area of the sector = 3 * 32π

<em>area of the sector =96π units²</em>

xxTIMURxx [149]2 years ago
5 0

Answer:

96π units²

Step-by-step explanation:

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Assume ABC DEF. If mA = 70 , mB = 47 , and mC = 63 , what is the measure of F? A. 63 B. 70 C. 47 D. Cannot be determined
kipiarov [429]
I'm assuming that the full statement is ΔABC is congruent to ΔDEF.

Given:
m∠A = 70
m∠B = 47
m∠C = 63

Since both triangles are congruent, the corresponding angles in ΔDEF also has the same measure as those in ΔABC.

m∠D = 70
m∠E = 47
m∠F = 63

The measure of angle F is 63.

5 0
2 years ago
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contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lots
Tju [1.3M]

The houses can be placed in 362,880 ways.

<u>Step-by-step explanation:</u>

The 9 houses are each in different design.

The each lot can place any of the 9 houses.

  • The 1st lot can place anyone house of all the 9 houses.
  • The 2nd lot can place one of remaining 8 houses.
  • The 3rd lot can place one of remaining 7 houses.

Similarly, the process gets repeated until the last house is placed on a lot.

<u>From the above steps, it can be determined that :</u>

The number of ways to place the 9 houses in 9 lots = 9!

⇒ 9×8×7×6×5×4×3×2×1

⇒ 362880 ways.

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5 0
2 years ago
Here is the histogram of a data distribution. All class widths are 1. What is the median of this distribution?
Bingel [31]

Answer:

The median is 4.

Step-by-step explanation

if you layout all the number, you get

1,2,2,3,3,3,4,5,5,5,6,6,7

So, to find the median you find the number(s) right in the middle.

(Ex. 3,4,5; 4 is the median)

(Ex. 3,4,5,7; 4.5 is the answer)

The middle number of

1,2,2,3,3,3,4,5,5,5,6,6,7

is 4, so 4 is the median.

hope this helps. :)

6 0
2 years ago
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Nikitich [7]

Answer:

The answer is given below

Step-by-step explanation:

Given that:

f(x)=\frac{1}{3}(81)^ \frac{3x}{4} \\Using\ exponent\ rule:a^{xy}=a^xa^y\\f(x)=\frac{1}{3}(81^{1/4})^ {3x}\\f(x)=\frac{1}{3}(3})^ {3x}\\f(x)=\frac{(3)^ {3x}}{3^1} \\Using\ exponent\ rule:a^x/a^y=a^{x-y}\\f(x)=3^ {3x-1}

The function is an exponential function.

The domain is the set of all independent variables i.e the input values (x values). For an exponential function, the domain is the set of all real numbers. That is:

Domain: x = (-∞, ∞)

The range is the set of all dependent variables i.e the values of y. For an exponential function, the range is the set of all real numbers greater than zero. That is:

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8 0
2 years ago
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Round 9,633,202 to the nearest million,
fiasKO [112]

Answer:

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Step-by-step explanation:

you round up, so that makes it 10,000,000

6 0
2 years ago
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