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Dahasolnce [82]
2 years ago
7

If m∠PTQ = 3y –10 and m∠QTR = y, find the value of y so that ∠PTR is a right angle

Mathematics
1 answer:
RideAnS [48]2 years ago
5 0

Answer:

y = 25

Step-by-step explanation:

Given that,

m∠PTQ = 3y –10 and m∠QTR = y

We need to find the value of y so that ∠PTR is a right angle.

For a right angle, one of the angle is 90 degrees. The sum of the angle of a triangle is equal to 180 degrees. So,

3y –10 + y + 90 = 180

Taking like terms together

3y+y = 180 -90 +10

4y = 100

y = 25

So, the value of y is 25.

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The regular octagon has a perimeter of 122.4 cm. A regular octagon with a radius of 20 centimeters and a perimeter of 122.4 cent
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Sam has some red and yellow cubes. She has 20 cubes in total. She has 8 more yellow cubes than red ones. How many red cubes does
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Write the equation of the line that is parallel to the line y=-7/4x-2 through the point (4,2)! Help please
Sladkaya [172]

as you already know, the equation y=-7/4x-2, is already in slope-intercept form and thus its slope is the coefficient of the "x", namely -7/4.

parallel lines have the same exact slope, so a parallel line to this one will also have a slope of -7/4, and it passes through 4,2,

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad \qquad \qquad  slope =  m\implies -\cfrac{7}{4} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=-\cfrac{7}{4}(x-4) \\\\\\ y-2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9

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2 years ago
In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the pro
postnew [5]

Answer:

The probability that more than half of them have Type A blood in the sample of 8 randomly chosen donors is P(X>4)=0.1738.

Step-by-step explanation:

This can be modeled as a binomial random variable with n=8 and p=0.4.

The probability that k individuals in the sample have Type A blood can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.4^{k} 0.6^{8-k}\\\\\\

Then, we can calculate the probability that more than 8/2=4 have Type A blood as:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\\\P(x=5) = \dbinom{8}{5} p^{5}(1-p)^{3}=56*0.0102*0.216=0.1239\\\\\\P(x=6) = \dbinom{8}{6} p^{6}(1-p)^{2}=28*0.0041*0.36=0.0413\\\\\\P(x=7) = \dbinom{8}{7} p^{7}(1-p)^{1}=8*0.0016*0.6=0.0079\\\\\\P(x=8) = \dbinom{8}{8} p^{8}(1-p)^{0}=1*0.0007*1=0.0007\\\\\\\\P(X>4)=0.1239+0.0413+0.0079+0.0007=0.1738

3 0
2 years ago
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