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AleksandrR [38]
2 years ago
9

Cameron wondered if the average score on a final exam was different between those who texted on a regular basis during the lectu

res for a particular class and those that did not text at all during the lectures. Which of the following statements is correct?
a. A one-tailed test should be performed since the alternative hypothesis states that the parameter is less than the hypothesized value.
b. A one-tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.
c. A two-tailed test should be performed since the alternative hypothesis states that the parameter s no e ua to he ypo es e alue.
d. A two-tailed test should be performed since the alternative hypothesis states that the parameter is less than the hypothesized value.
e. A two-tailed test should be performed since the null hypothesis states that the parameter is not equal to the hypothesized value.
Mathematics
1 answer:
Margarita [4]2 years ago
3 0

Answer:

c. A two-tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.

Step-by-step explanation:

Let p1 be the average score on a final exam who texted on a regular basis during the lectures for a particular class

And p2 be the average score on a final exam who did not texted at all during the lectures for a particular class

According to the Cameron's point of interest, null and alternative hypotheses are:

H_{0}: p1 = p2

H_{a}: p1 ≠ p2

Two tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.

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If the three integers are a,b,c, then we have

\dfrac1a+\dfrac1b+\dfrac1c=1

We can combine the fractions on the left side:

\dfrac{bc}{abc}+\dfrac{ac}{abc}+\dfrac{ab}{abc}=\dfrac{bc+ac+ab}{abc}=1

\implies abc=bc+ac+ab

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2 years ago
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A sixth grade teacher takes students on a field trip to the beach. One student finds several pebbles that have a rounded shape a
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The shape of the pebbles is a result of weathering and deposition.

Step-by-step explanation:

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1 year ago
Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the varia
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Answer:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property.

Step-by-step explanation:

Given the polynomial :

80b⁴ – 32b²c³ + 48b⁴c

The Greatest Common Factor (GCF) of the coefficients:

80, 32, 48

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80

32 : 1, 2, 4, 8, 16, and 32

48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

GCF = 16

b⁴, b², b⁴

b⁴ = b * b * b * b

b² = b * b

b⁴ = b * b * b * b

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GCF of c³ and c

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c = c

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We can see that David's GCF of the coefficients are all correct

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1,496 new car buyers

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e = 0.02 is the margin of error

so  

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It can be obtained in Excel or OpenOffice Calc with

<em>NORMSINV(0.95)</em>

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h=Lsinα  so

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