Answer:
200
Step-by-step explanation:
Given:
0.482 x 61.2^2 ÷ √98.01
61.2^2 = 3745.44
√98.01 = 9.9
So,
0.482 × 3745.44 ÷ 9.9
= 1,805.30208 ÷ 9.9
= 182.35374545454
To one significant figure
= 200
One significant figure means only 1 non zero value and others are zero
Answer: 8:05 pm
Step-by-step explanation: 4 hours + 3 hours = 7 hours
50 min + 15 min = 1 hour, 5 min
add those together
watch out for time zones when crossing
Given that function H(t) models the height of Pooja's plant (in centimeters) where t is the number of days after she bought it.
Now we have to find about which number type is more appropriate for the domain of h. That means what values can be taken by the variable "t".
Since t is number of days not the hours so t will not use decimal or fraction values. It can use integer values for the number of days.
Since time is counted after she bought the plant then number of days will be positive.
Hence answer for the type of domain can be positive integers or you can say integers greater than or equal to 0.
Answer:
The answer is 51,200 bacterium.
Step-by-step explanation: So you need to figure out the time between 12 and 6pm, then divide it by 40. 12-6 is 360 minutes, you divide by 40 and you get 9 divisions. Multiply the 100 x 2=200, 200 x 2 =400, and so on for 9 times.
You get a result of 51,200 bacterium.
The second question:
Consider the division expression 
. Select all multiplication equations that correspond to this division expression.
Answer:
1. See Explanation
2. and
Step-by-step explanation:
Solving (a):
Given
Required
Interpret 
in 2 ways
<u>Interpretation 1:</u> Number of groups if there are 5 students in each
<u>Interpretation 2:</u> Number of students in each group if there are 5 groups
<u>Solving the quotient</u>
<u>For Interpretation 1:</u>
The quotient means: 12 groups
<u>For Interpretation 2:</u>
The quotient means: 12 students
Solving (b):
Given
Required
Select all equivalent multiplication equations
Let ? be the quotient of t
So, we have:
Multiply through by 2
Rewrite as:
--- This is 1 equivalent expression
Apply commutative law of addition:
--- This is another equivalent expression
