There are two sets of data: Erika's and Rita's. Now, we have to find the average values for each of both and compare them. I would assume that the order of the presentation of data points is alternating, first for Erika followed by Rita. To illustrate what I mean, let's say in Day 1, Erika's time is 20 and Rita's time is 21.25. In Day 2, Erika's time is 21.5 and Rita's is 24.75. And so on and so forth. The complete tabulation is shown in the picture.

Erika's average = (20+21.5+22.75+23.25+20.25)/5 = 21.55
Rita's average = (21.25+24.75+23+23+20.75)/5 = 22.55

On average, Erika is much slower than Rita by 1 minute.

7 0

2 years ago

The surface areas of two similar figures are 4 in2 and 9 in2. If the volume of the larger figure is 216 in3, what is the volume

OverLord2011 [107]

We know that
surface area smaller figure=scale factor²*surface area larger figure
scale factor=√[surface area smaller figure/surface area larger figure]
scale factor=√[4/9]-----> scale factor=2/3
so
volume smaller figure=scale factor³*volume larger figure
volume smaller figure=(2/3)³*216----> (8/27)*216----> 64 in³

the answer is
the volume of the smaller figure is 64 in³

8 0

2 years ago