Answer:
Do you have answer choices
Step-by-step explanation:
Answer:
x = 5
Step-by-step explanation:
Step 1: Write equation
-3/4 + 2/5x = 7/20x - 1/2
Step 2: Subtract 7/20x on both sides
-3/4 + 1/20x = -1/2
Step 3: Add 3/4 to both sides
1/20x = 1/4
Step 4: Divide 1/20 on both sides
x = 5
Answer:
0.94
Step-by-step explanation:
The question after this basically is:
<em>"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"</em>
<em />
So,
P(successful if hired) = 60% = 0.6 [let it be P(x)]
P(success at passing the test) = 85% = 0.85 [let it be P(y)]
P(successful and pass the test) = P(x) + P(y) -[P(x)*P(y)]
So,
P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)
Answer:
1131 pounds.
Step-by-step explanation:
We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.
First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:
The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.
Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.
Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.
Answer:
Step-by-step explanation:
For the random variable 
we define the possible values for this variable on this case ![[1,2,3,4,5]](https://tex.z-dn.net/?f=%20%5B1%2C2%2C3%2C4%2C5%5D)
. We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:
We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable 
like this:
For the distribution of 
we need to take in count that we are finding a conditional distribution. given 
, for this case we see that ![N_2 \in [1,2,...,5-a]](https://tex.z-dn.net/?f=%20N_2%20%5Cin%20%5B1%2C2%2C...%2C5-a%5D)
, so then exist 
ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:
And if we want to find the joint probability we just need to do this:
And if we multiply the probabilities founded we got:
