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2 years ago

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A survey asked students at Wilson Academy which status they would prefer—to be happy, healthy, or rich—and how much pressure the

y felt from their homework. The two-way table of row relative frequencies below shows the data.

1 answer:

Brrunno [24]2 years ago

7 0

Answer:

A. A student who prefers to be healthy is more likely to feel very little pressure from homework than a student who prefers to be rich.

Step-by-step explanation:

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Which real numbers are zeros of the function? f(x)=2x3−x2−8x+4 Select each correct answer. −2 −1 −12 0 12 1 2

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Answer:

Step-by-step explanation:

Given is a function in x as

$f(x)=2x^3-x^2-8x+4$

We have to find the zeroes of the function

Since this is a cubic function this function has three zeroes.

Let us try to factorise this function by grouping two terms together.

$x^2(2x-1)-4(2x-1)\\= (2x-1)(x^2-4)$

= $(2x-1)(x-2)(x+2)$

Equate each factor to 0 to find zeroes as

$-2,2,\frac{1}{2}$

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1 year ago

Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic

Delicious77 [7]

10 x 62 is the equation for this problem because every row has 62 and there are 10 rows.

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2 years ago

A function f on [a, b] is called a step function if there exists a partition P = {a = u0 < u1 < ··· < cm = b} of [a, b]

Arturiano [62]

Answer:

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Step-by-step explanation:

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2 years ago

A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th

QveST [7]

we know that

the volume of a cone is equal to

$V= \frac{1}{3} \pi r^{2}h$

in this problem

the radius is equal to

$r= \frac{112}{2}= 56ft$

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

$h^{2} = l^{2}-r^{2}$

$l=65 ft$

$h^{2} = 65^{2}-56^{2}$

$h^{2} = 1,089$

$h=33 ft$

2) <u>Find the volume before the storm</u>

$V= \frac{1}{3}*\pi* 56^{2}*33$

$V=34,496\pi\ ft^{3}$

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

$V= \frac{1}{3}*\pi* (56/3)^{2}*11$

$V= 1,277.63\pi\ ft^{3}$

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

$\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}$

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is $\frac{1}{27}$ times the original volume

<u>Part b)</u> Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

$=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}$

6) <u>Find the pounds of road salt used</u>

$104,358.59*80=8,348,687.2\ pounds$

7) <u>Find the number of lane miles that were covered with salt</u>

$8,348,687.2/350=23,853.39 \ lane\ miles$

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is $23,853.39 \ lane\ miles$

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to $1,277.63\pi\ ft^{3}$

$1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}$

8) <u>Find the pounds of road salt </u>

$4,013.79*80=321,103.20\ pounds$

9) <u>Find the number of lane miles </u>

$321,103.20/350=917.44 \ lane\ miles$

therefore

<u>the answer part c) is</u>

the number of lane miles is $917 \ lane\ miles$

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2 years ago

The difference of two numbers is 20 and their product is 125, what is the answer?

brilliants [131]

find prime factors to get the inbetween numbers for product, and choose the one that has a difference of 20, and it should be 5 and 25, both requirements are met.

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2 years ago

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