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Pavlova-9 [17]
2 years ago
9

A school cafeteria sells milk at 25 cents per carton and salads at 45 cents each. one week the total sales for these items were

$132.50. how many salads were sold that week?
Mathematics
1 answer:
denis-greek [22]2 years ago
4 0

solution:

Lets start with the most amount that could have been sold.......using guess and check, we can figure out that 290 salads could have been sold, while 8 cartons of milk would have been sold.

The least amount of salads that could have been sold were none.

so,

you have  0<s<290

at least none were sold, and at most 290 were sold

but I do believe you are missing part of the question


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If b is the midpoint of ac, ac=cd, ab=3x+4, ac=11x-17, and ce=49, find de
IrinaK [193]

First, we draw our line.

 

|------------------------------------------------------------------------------------|

a                                                                                                            e

 

 

Next, break up this line into segments using the information.

 

|----------------------|----------------------|--------------------|------------------|

a                            b                            c                         d                      e

 

 

The entire line is 29.

 

ab + bc + cd + de = ae

ab + bc + cd + de = 29

 

You also know that

 

bd = bc + cd

 

 

Due to midpoint theorem,

 

ab = bc

cd = de

 

 

Then,

 

2ab + 2cd = 29

 

 

The equations we will use are

 

bd = bc + cd                       eq1

2bc + 2cd = 29                   eq2

 

 

Dividing both sides of the equation in eq2 yields

 

bc + cd = 14.5

 

bd = bc + cd

bd = 14.5

5 0
2 years ago
Read 2 more answers
What is the slope intercept form of (3,3) (7,-1)
kow [346]
Slope intercept form follows this general equation...
y=mx+b
With this information you have posted, all you can do is find slope, your m. To calculate for slope, you need to use this following equation...
m= \frac{y_2-y_1}{x_2-x_1}
Then, you pick one of your coordinate pairs to be 1 and the other to be 2. I will choose the first coordinate pair as 1, so...
m=\frac{-1-3}{7-3} =-1
You plug in -1 into your slope formula...
y=-1x+b
Now, to find your y-intercept, or b, you must plug in one of your coordinate pairs. In that equation, you may plug in the values (3,3), so you'll have...
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Just solve for b and you will be done
5 0
1 year ago
David made a class banner out of a large rectangular piece of paper. He cut a
Irina18 [472]

Answer:

100 in²

Step-by-step explanation:

The area of the banner is equal to the area of the initial rectangle minus the area of the cutout triangle.

The rectangle has a height of 8 inches and width of 14 inches, so its area is:

A = (8 in) (14 in) = 112 in²

The triangle has a base of 8 inches and a height of 3 inches, so its area is:

A = ½ (8 in) (3 in) = 12 in²

So the area of the banner is 112 in² − 12 in² = 100 in².

6 0
2 years ago
Using the side-splitter theorem, which segment length would complete the proportion?
tia_tia [17]

we know that

<u>The Side-Splitter Theorem</u>: States that If a line is parallel to one side of a triangle and intersects the other two sides, then it divides those two sides proportionally

so

in this problem

\frac{GH}{HE} =\frac{GJ}{JF}

therefore

<u>the answer is</u>

The segment length is GJ

5 0
2 years ago
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Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.
Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

A=\frac{3\sqrt{3} }{2} r^2

Where r is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid:A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2

From these areas we find the radius of the hexagons:

r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}

r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that r_1 r_2 form similar triangles with length H

Therefore we have:

\frac{H-8}{r_1} =\frac{H}{r_2}

We put in the numerical values of r_1, r_2 and solve for H:

\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}

8 0
2 years ago
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